You have not mention here about those elements but the general concept for this is the:
uneven distribution ------> polar
even distribution -------> non-polar
Empirical formula is the simplest ratio of whole numbers of components in a compound
in 100 g of compound
C H O
mass 25.5 g 6.40 g 68.1 g
number of moles 25.5 g/12 g/mol 6.40 g/ 1 g/mol 68.1 g/ 16 g/mol
= 2.13 mol = 6.40 mol = 4.26 mol
divide by least number of moles
2.13/2.13 = 1 6.40/2.13 = 3.0 4.26/2.13 = 2.0
all rounded off
C - 1
H - 3
O - 2
empirical formula - CH₃O₂
Answer:
Cl
Si
Mg
Na
Explanation:
Ionization energy is the energy required to remove an electron from the valence shell of an atom to form an ion. Since metal are natural givers, they help people. Non metals are receivers hence it would be very hard for them to release their electrons.
For our arrangement, the key is that the ionization energy is expected to increase across the period to a maximum that terminates at the halogens. This is the more reason why halogens have the highest ionization energy and the alkali metals have the lowest.
Hence, from the options in the question, we can see that chlorine would have the highest because it is an halogen in group 17. Also expected is the fact that the ionization energy of that Mg is greater than that if Na. This is because Mg comes after Na in the same period and is thus expected to have higher ionization energy than Na
