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3 years ago

What is the molarity of a solution that contains 40.

Chemistry

1 answer:

Allushta [10]3 years ago

8 0

Answer:

Explanation:

because it be an the only answer there

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Anvisha [2.4K]

Answer:

bro what Is this like I dont even kno

7 0

2 years ago

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In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the

BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

$2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)$

$K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0

3 years ago

Draw the structure of the fat or oil that would result when a glycerol molecule is

charle [14.2K]

Glycerol will react with 3 butanoic acid molecule to produce glyceryl tributyrate.

Explanation:

You may find the chemical reaction and the structure of molecules in the attached picture.

Learn more about:

triglyceride

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3 0

3 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

<u>Answer:</u> The mass of HCl present in 500 mL of acid solution is 36.5 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0

3 years ago

If 1.546 g of copper was used by a student at the start of the lab, and 0.732 g of copper were obtained at

mash [69]

Answer: Percent recovery is 47.34 %

Explanation:

Percent yield is defined as the ratio of experimental yiled to theoretical yield in terms of percentage.

${\text{ percent yield}}=\frac{\text{amount recovered}}{\text{total amount}}\times 100$

Putting in the values we get:

${\text{ percent yield}}=\frac{0.732}{1.546}\times 100=47.34\%$

Therefore, the percent recovery is 47.34 %

8 0

3 years ago