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3 years ago

The point (3,-4) is on the terminal side of an angle 0. What is cos 0?

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

9514 1404 393

Answer:

C. 3/5

Step-by-step explanation:

The distance from the origin to the given point is ...

d = √(3² +(-4)²) = √(9+16) = 5

The cosine of the angle is the ratio of the x-coordinate to this value:

cos(θ) = x/d

cos(θ) = 3/5

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What is the total surface area of a cylindrical tank having

UkoKoshka [18]

Answer:

Could be C) or D) None of these, 29688.05cm^2

Step-by-step explanation:

Did the question to round off to any numbers?

Formula for cylinder's T.S.A: 2 π r h + 2 π r^2

Diameter= 2 x radius

Radius = 70cm / 2 = 35cm

Height -> need to convert m to cm -> 100cm

Substitute these values into the formula:

2 x π x 35 x 100 + 2 x π x (35)^2 = 29688.05cm^2

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3 years ago

Q2:

anygoal [31]

Answer: rectangular prism

Step-by-step explanation:

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3 years ago

21 cans of tomato paste of the same size have weight of 7300 grams. What is the weight of 5 cans.

vesna_86 [32]

Answer:

answer is 347.6

Step-by-step explanation:

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2 years ago

Richard is given one of four pieces of equal-sized fabric. After using some of his fabric for a project, he has 5/6 of a square

ValentinkaMS [17]

Answer:

Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

Step-by-step explanation:

Given:

Total amount of fabric = $11\frac23\ yd^2$

Now To convert a mixed fraction to an improper fraction, Multiply the whole number part by the fraction's denominator, Add that to the numerator,Then write the result on top of the denominator.

$11\frac23\ yd^2$ can be Rewritten as $\frac{35}{3}\ yd^2$

Number of pieces fabric was cut = 4

Richard is given one of four pieces of equal-sized fabric.

Amount of fabric Richard was given = $\frac14 \times \frac{35}{3}=\frac{35}{12}\ yd^2$

Amount of fabric left with Richard = $\frac56 \ yd^2$

We need to find the amount of fabric Richards used for his project.

Solution:

Now we can say that;

amount of fabric Richards used for his project is equal to Amount of fabric Richard was given minus Amount of fabric left with Richard.

framing in equation form we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac56$

Now we will make the denominator common using LCM we get;

amount of fabric Richards used for his project = $\frac{35}{12}-\frac{5\times2}{6\times2} = \frac{35}{12}-\frac{10}{12}$

Now Denominator is same so we will solve the numerator.

amount of fabric Richards used for his project = $\frac{35-10}{12}= \frac{25}{12}\ yds^2$

$\frac{25}{12}\ yds^2$ can be rewritten as $2\frac{1}{12}\ yd ^2$

Hence Richard used $2\frac{1}{12}\ yd ^2$ of fabric for his project.

7 0

3 years ago

There’s a picture so I don’t have to type out the question

Lorico [155]

For this case we have the following function:

$s (V) = \sqrt [3] {V}$

This function describes the side length of the cube.

If Jason wants a cube with a minimum volume of 64 cubic centimeters, then we propose the following inequality:

$s \geq \sqrt [3] {64}$

Rewriting we have:

$s \geq \sqrt [3] {4 ^ 3}\\s \geq4$

Answer:

Option B

3 0

3 years ago