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4vir4ik [10]
3 years ago
11

Jeff and Marcia own a llama farm. On their farm, they have 240 llamas.

Mathematics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

Step-by-step explanation:

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Twelve friends came to Guy’s birthday party. He received seven gifts and a total of $95 in cash for his birthday. He buys an air
V125BC [204]
$95-$9 = $86 / $8 = 10 animal shelters with a remainder of $6

I hope this helps! :)
4 0
3 years ago
Read 2 more answers
Upon descent, an airplane is 20,000 feet above the ground. The air traffic control tower is 200 feet tall. It is determined that
PIT_PIT [208]

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

6 0
3 years ago
Two trains, Train A and Train B, weigh a total of 312 tons. Train A is heavier than Train B. The difference of their weights is
Korvikt [17]
312-170=142
142÷2=71
170+71=241
241+71=312
train A weighs 241 tons
7 0
3 years ago
Simplify (2a+5)6a^2<br> Can someone help please
Wewaii [24]

Answer:

12a^3+30a^2

Step-by-step explanation:

6a^2(2a+5)

12a^3+30a^2

5 0
3 years ago
In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.
zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are {13 \choose 2} = 78 elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are {11 \choose 2} = 55 possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

  • A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
  • One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

5 0
3 years ago
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