Answer:
111.15 g are required to prepare 500 ml of a 3 M solution
Explanation:
In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.
Since 1 mol of Ca(OH)₂ has a mass of 74.1 g, 1.5 mol will have a mass of
(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.
Answer:
it can cause irritation in eyes throat and lungs and u can become lightheaded, or possibly fall in a coma
0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
<h3>What do mean by the term "gallons" ?</h3>
The gallon is a unit of measurement for volume and fluid capacity in both the US units and the British imperial systems of measurement.
In SI base units, 1 Gal is equal to 0.01 m/s²
Since ,
1 L, l = 0.2641720524 gal
now, volume of acid in gallons is given by -
2.3 L, l = 2.3 × 0.2641720524 gal
=0.60759572 gal
Hence , 0.60759572 gal is the volume of acid in gallons in a sample of hydraulic acid .
Learn more about gallon ,here:
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Answer:
B how much farther does the arrow fly when you use a stronger bow
Explanation:
