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Xelga [282]
3 years ago
10

I need an example of a chemical change involving water.Pleaseeee.

Chemistry
1 answer:
slava [35]3 years ago
7 0
Chemical change occur when two substances are combined and produces a new substance or decomposes into two or more substances which are entirely different from the original two substances.

There are three types of chemical changes. These are 1) Inorganic Changes, 2) Organic Changes, and 3) Biochemical Changes


Here are some examples of chemicsal changes.

If you combine Sodium and Water, chemical changes causes decomposition into Sodium Hydroxide and Hydrogen.

Sodium + Water  ==>  Sodium Hydroxide and Hydrogen

Na + H2O ====>  NaOH and H

Another example of chemical change is:

Carbon Dioxide and Water will decompose into Sugar and Oxygen

Carbon Dioxide + Water ==> Sugar and Oxygen

CO2 + H2O ==> CnH2nOn (where n is between 3 and 7) and O

 
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A gas with a volume of 4.0 L at a pressure of 2.02 atm is allowed to expand to a volume of 12.0
Maurinko [17]
<h3>Answer:</h3>

P₂ = 0.67 atm

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Gas Laws</u>

Boyle's Law: P₁V₁ = P₂V₂

  • P₁ is pressure 1
  • V₁ is volume 1
  • P₂ is pressure 2
  • V₂ is volume 2
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] P₁ = 2.02 atm

[Given] V₁ = 4.0 L

[Given] V₂ = 12.0 L

[Solve] P₂

<u>Step 2: Solve</u>

  1. Substitute in variables [Boyle's Law]:                                                              (2.02 atm)(4.0 L) = P₂(12.0 L)
  2. [Pressure] Multiply:                                                                                           8.08 atm · L = P₂(12.0 L)
  3. [Pressure] [Division Property of Equality] Isolate unknown:                          0.673333 atm = P₂
  4. [Pressure] Rewrite:                                                                                           P₂ = 0.673333 atm

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our smallest.</em>

0.673333 atm ≈ 0.67 atm

4 0
3 years ago
Explain how percent yield is calculated
Alex73 [517]
Actual yield/theoretical yield x 100
4 0
3 years ago
Which product forms from a reaction between calcium (Ca) and phosphorus
IrinaVladis [17]

Answer:

A

Explanation:

3 0
3 years ago
Read 2 more answers
4. Finally, convert hemoglobin concentration from g/dL to millimoles per Liter (milliMolar or mM). Hemoglobin has a molecular we
prohojiy [21]

To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water

The molecular weight of Hemoglobin is approximately  16,000 Daltons, when hemoglobin is converted to mM

16000 Dalton = 16000 ( g/mol )

given that 1 Dalton = 1 g/mol

To make 1 molar solution of hemoglobin using 1 liter of water

1 liter = 1000 grams

16000 Dalton = 16000 g/mol

Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.

learn more : brainly.com/question/23517096

8 0
3 years ago
A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?
jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} = k

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1} =\frac{V2}{T2}

In this case, you know:

  • V1= 40 L
  • T1= 90 °C
  • V2= ?
  • T2= 186 °C

Replacing:

\frac{40L}{90C} =\frac{V2}{186 C}

Solving:

V2=\frac{40L}{90C} *186 C

V2= 82.67 L

<u><em>The volume will be 82.67 L</em></u>

5 0
3 years ago
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