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We can see that the solubility of salt increases with increasing temperature. This happens with most substances.
To find out the maximum mass of copper sulfate that can be dissolved in water at these temperatures, just interpret the graph.
Considering Y-axis as g copper sulfate/100 g water and the X-axis as the temperature in °C:-
<u>1)</u>
a: <u>0 °C - 14 g of copper sulfate/100 g of water</u>
b: <u>50 °C - 34 g of copper sulfate/100 g of water</u>
c: <u>90 °C - 66 g of copper sulfate/100 g of </u><u>water</u>
<u>2)</u> From the graph, we can infer that temperature affects the solubility of the salt.
<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin360</em><em> </em>:)
Answer:
0.9483 grams of manganese dioxide should be added to excess HCl.
Explanation:
Pressure of the chlorine gas = P = 795 Torr = 1.046 atm (1 atm = 760 Torr)
Volume of the chlorine gas = V = 255 ml = 0.255 L
Temperature of the chlorine gas = T = 25°C= 298.15 K
Moles of chlorine gas = n
Using ideal gas equation:
PV = nRT

n = 0.01090 mol

According to reaction , 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide.
Then 0.01090 moles of chlorine gas will be obtained from:
manganese dioxide
Mass of 0.01090 moles of manganese dioxide:
0.01090 mol × 87 g/mol = 0.9483 g
Given in the problem is the mass of the liquid (500 grams) and the volume of the liquid (1000 ml = 1000 cm^3).
We can use these two givens to calculate the density of the liquid using the following rule:
density = mass / volume
density = 500 / 1000 = 0.5 grams / cm^3
Comparing the calculated density with the choices we have, we can deduce that the liquid is most likely to be propane with density 0.494 g / cm^3
Answer:
8.31 × 10⁻²² kJ
Explanation:
Step 1: Given data
Energy required to remove one mole of electrons from the atoms at the surface of a solid metal: 500 kJ/mol e⁻
Step 2: Calculate how much energy does it take to remove a single electron from an atom at the surface of this solid metal
We will use Avogadro's number: there are 6.02 × 10²³ electrons in 1 mole of electrons.
500 kJ/mol e⁻ × 1 mol e⁻/6.02 × 10²³ e⁻ = 8.31 × 10⁻²² kJ/e⁻