Answer:
A sample of 385 is needed.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
That is z with a pvalue of , so Z = 1.96.
Now, find the margin of error M as such
In which is the standard deviation of the population, which is the square root of the variance, and n is the size of the sample.
Assume the variance is known to be 3.61.
This means that
How large of a sample would be required in order to estimate the mean number of reproductions per hour at the 95% confidence level with an error of at most 0.19 reproductions?
A sample of n is needed.
n is found when . So
Rounding up
A sample of 385 is needed.
Inequality: y - 5 ≥ 8
Add 5 to both sides: y - 5 + 5 ≥ 8 + 5
Combine like terms: y ≥ 13
On a graph, this will look like the image shown. This is because the ≥ symbol means that the variable (y) is greater than or equal 13, so all numbers bigger than 13, including 13, are valid answers.
Answer:
Median: 2 goals
Mean: 2 goals
Step-by-step explanation:
Let's go over the definitions of the terms "median" and "mean",
Median: The number in the middle of the data; the value in the middle of a range of values
Mean: The average number between all values in a range of values
To find the median, let's first look at all the numbers in the data. We're trying to find the median conceded goals, so the numbers are:
0
1
2
3
4
Now, let's find the middle number. Cross off 0 and 4, 1 and 3, and we are left with 2. 2 is the median.
To find the mean, or the average, we must add all of the numbers together, and then divide that number by the amount of terms. There are 5 terms. Let's review them again.
0
1
2
3
4
Add them together to get 10. Then, since there are 5 values, divide by 5. 10/5 = 2. So, the mean is 2.
I think it would have to be 5
i don't know i could be wrong but chances are 2
Answer:
The mean is 2.
The interquartile range is also 2.
Step-by-step explanation:
Sorry if it's wrong.
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