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3 years ago

Pleaseee helppp (5x^2y^3)^2

Mathematics

1 answer:

Tamiku [17]3 years ago

5 0

Answer:

25x⁴y⁶

Step-by-step explanation:

From what I understand your question looks like this

(5x²y³)²

To solve this just mulitply

5x²y³*5x²y³

$a^x*a^n=a^{x+n}$

25x⁴y⁶

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Cual es el volumen de un cubo que tiene como area exterior 1.176 cm2 ??

photoshop1234 [79]

Answer:

1.63

Step-by-step explanation:

V≈1.63

4 0

3 years ago

A student's grades in the three tests in College Algebra are 85, 60, and 69. a) How many points does the student need on the fin

Anastaziya [24]

Answer:

(a) The student need 82 points on the final to average 74.

(b) The student must score 41 points on the final, assuming that the final carries double the weight.

Step-by-step explanation:

We are given that a student's grades in the three tests in College Algebra are 85, 60, and 69.

As we know that the formula for calculating the average of numbers is given by;

Average (Mean) = $\frac{\text{Sum of all values}}{\text{Number of observations}}$

(a) Let the points student need on the final test to average 74 be ' $x$ '.

So, Average of all four test = $\frac{85+60+69+x}{4}$

$74 = \frac{85+60+69+x}{4}$

$74 = \frac{214+x}{4}$

$214+x =74 \times 4$

$x = 296-214$

$x=82$

Hence, the student needs 82 points on the final to average 74.

(b) It is given that the final carries double the weight, this means that let the points student need on the final test to average 74 be ' $2x$ '.

So, Average of all four test = $\frac{85+60+69+2x}{4}$

$74 = \frac{85+60+69+2x}{4}$

$74 = \frac{214+2x}{4}$

$214+2x =74 \times 4$

$2x = 296-214$

$x=\frac{82}{2}$ = 41

Hence, the student must score on the final 41 points, assuming that the final carries double the weight.

7 0

3 years ago

Write the equation of the line that is parallel to the graph of Y=1/2 X +6 and his Y intercept is -2

kakasveta [241]

Answer: x=0

Step-by-step explanation: Find any equation parallel to the line.

Hope this helps you out! If you need anymore help, I am more than happy to help you out if you need it! ☺

-Karleif Jonsi-

8 0

3 years ago

Its really urgent. I need help with the first question.

RUDIKE [14]

This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.

a). sin · cot / sec

You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].

Then the problem becomes

sin · (cos/sin) / (1/cos) = cos²

Aw shucks, I might as well also set up 'b)' for you:

b). cos · csc / tan

You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].

Then the problem becomes

cos · (1/sin) / (sin/cos) = (cos/sin)²

Now simply plug in the given values of cos A and sin A .

And may I compliment you on your nail care !

7 0

3 years ago

A fourth grade class of 28 students is given a standardized math test. The mean score of the 12 boys is 25 with a standard devia

Mashcka [7]

Answer:

The standard error for the sampling distribution is 1.323.

Step-by-step explanation:

Let X = scores of girls and Y = scores of boys.

The information provided is:

$\bar x=24\\s_{x}=4\\n_{x}=16\\\bar y=25\\s_{y}=3\\n_{y}=12$

As the population standard deviations are not known, use a pooled standard deviation to estimate the standard error of the sampling distribution.

The formula of pooled standard deviation is:

$S_{p}=\sqrt{\frac{s_{x}^{2}}{n_{x}^{2}}+\frac{s_{y}^{2}}{n_{y}^{2}}}$

Compute the standard error for the sampling distribution as follows:

$SE=\sqrt{\frac{s_{x}^{2}}{n_{x}^{2}}+\frac{s_{y}^{2}}{n_{y}^{2}}}=\sqrt{\frac{4^{2}}{16}+\frac{3^{2}}{12}}=\sqrt{1+\frac{9}{12}}=\sqrt{\frac{21}{12}}=1.323$

Thus, the standard error for the sampling distribution is 1.323.

7 0

3 years ago