Which activity constitutes legal computer activity?

You are a psychologist who needs to provide a qualitative evaluation for IQ scores. Create a program that takes IQ scores (one a

dsp73

Answer:

Check the explanation

Explanation:

#include <iostream>

#include <iomanip>

using namespace std;

int getIQ(); // return the score

void printEvaluation(int);

int main()

{

int IQ = 0;

IQ = getIQ();

printEvaluation(IQ);

return 0;

}

int getIQ()

{

int score = 0;

cout << "Please enter your IQ Score to receive your IQ Rating:\n";

cin >> score;

return score;

}

void printEvaluation(int aScore)

{

cout << "IQ Score: " << aScore << " IQ Rating: ";

if (aScore <= 100)

{

cout << "Below Average\n";

}

else if (aScore <= 119)

{

cout <<"Average\n";

}

else if (aScore <= 160)

{

cout << "Superior\n";

}

else if (aScore >= 160 )

{

cout << "Genius\n";

}

4 0

3 years ago

The document asks about dependents because the number can

BARSIC [14]

The answer is: Lower overall taxes

8 0

3 years ago

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What policy definition can help remind employees in the User Domain about what constitutes suitable use and improper use of corp

Helga [31]

Answer:

so so sorry I don't know

Explanation:

hope fully you'll get the answer

4 0

3 years ago

Write a series of conditional tests. Print a statement describing each test and your prediction for the results of each test. Fo

N76 [4]

Answer:

this:name = 'John'

print("Is name == 'John'? I predict True.")

print(name == 'John')

print("\nIs name == 'Joy'? I predict False.")

print(car == 'Joy')

this:age = '28'

print("Is age == '28'? I predict True.")

print(age == '28')

print("\nIs age == '27'? I predict False.")

print(age == '27')

this:sex = 'Male'

print("Is sex == 'Female'? I predict True.")

print(sex == 'Female')

print("\nIs sex == 'Female'? I predict False.")

print(sex == 'Joy')

this:level = 'College'

print("Is level == 'High School'? I predict True.")

print(level == 'High School')

print("\nIs level == 'College'? I predict False.")

print(age == 'College')

Conditions 1 and 2 test for name and age

Both conditions are true

Hence, true values are returned

Conditions 3 and 4 tests for sex and level

Both conditions are false

Hence, false values are returned.

7 0

3 years ago

If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support

Molodets [167]

Answer:

Here is the JAVA program. I have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); // create object of Scanner

String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

String LOL = "laughing out loud";

String IDK = "i don't know";

String BFF = "best friends forever";

String IMHO = "in my humble opinion";

String TMI = "too much information";

String TYT = "take your time";

String IDC = "I don't care";

String FYI = "for your information";

String BTW = "by the way";

String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

System.out.println("Input an abbreviation:" + " ");

if(input.hasNext()) { // reads the abbreviation form the user

abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

switch(abbreviation) {

case "LOL" : System.out.println(LOL);

break;

case "IDK" : System.out.println(IDK);

break;

case "BFF" : System.out.println(BFF);

break;

case "IMHO": System.out.println(IMHO);

break;

case "TMI": System.out.println(TMI);

break;

case "TYT": System.out.println(TYT);

break;

case "IDC": System.out.println(IDC);

break;

case "FYI": System.out.println(FYI);

break;

case "BTW": System.out.println(BTW);

break;

case "OMG": System.out.println(OMG);

break;

default : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0

3 years ago

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