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Bumek [7]
3 years ago
8

A cylinder of clay has a diameter of 12 cm and a height of 12 cm. If this clay is made into congruent cones with a radius of 3 c

m and a height of 8 cm, how many cones could be made with all of the clay?If you used all the clay, you could make
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

Step-by-step explanation:

volume of the cyclinder=πr²h

=π×6²×12

=432π cm³

volume of a cone=1/3πr²h

=1/3π×9×8

=24π cm³

number of cones=432π/24π=18 cones

You might be interested in
One side of triangle is 4 4 times the shortest side. The third side is 23 23 feet more than the shortest side. The perimeter is
jasenka [17]

Answer:

9, 32 and 36

Step-by-step explanation:

The perimeter of a triangle is the sum of all the sides.  Since you know the perimeter and the expressions for each of the sides, you can set up an equation to solve for the variable and find the values of the other sides:

one side: '4 times the shortest side' = 4s

shortest side: 's'

third side: '23 more than the shortest side' = s + 23

perimeter  = 77

Equation:  4s + s + (s + 23) = 77

Combine like terms:  6s + 23 = 77

Subtract 23 from both sides:  6s + 23 - 23 = 77 - 23 or 6s = 54

Divide by 6:  6s/6 = 54/6 or s = 9

one side: 4s = 4(9) = 36

shortest side: s = 9

third side: s + 23 = 9 + 23 = 32

3 0
3 years ago
The line contains the point (-2,-5) and is parallel to 2x-3y = 9.<br> What’s the equation
Karolina [17]

Answer:

y=(2x/3)-(11/3)

Step-by-step explanation:

https://www.emathhelp.net/calculators/algebra-1/parallel-and-perpendicular-line-calculator/

7 0
3 years ago
Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an
Leya [2.2K]
Parameterize the lateral face T_1 of the cylinder by

\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v

where 0\le u\le2\pi and 0\le v\le3, and parameterize the disks T_2,T_3 as

\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)

where 0\le r\le2 and 0\le\theta\le2\pi.

The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr
=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr
=136\pi
7 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
3 years ago
Could someone explain this.Brainliest
True [87]

Simplify 1/4x to x/4

-x/4 - 14y - 1/8x + 2y + 18

Simplify 1/8x to x/8

-x/4 - 14y - x/8 + 2y + 18

Collect like terms

(-x/4 - x/8) + (-14y + 2y) + 18

Simplify

-3/8x - 12y + 18

4 0
3 years ago
Read 2 more answers
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