Answer:
Step-by-step explanation:
Could you maybe repost this question with an screenshot of the number line?
This method can be very useful, so please try to remember it
Let's find a common factor for the two denominators (10 and 8) to make the two fractions combinable.
We need to find a number that can be divisible by 10 and 8 (denominators). Right off the bat, we can just multiply the two numbers and get 8 x 10 = 80.
Then let's make the numerators correspond to the denominators.
8/10 = x/80 Set up a proportion.
10x = 640 Cross-multiplication.
x = 64 Divide and simplify.
3/8 = x/80 Set up a proportion.
8x = 240 Cross-multiplication.
x = 30 Divide and simplify.
Now we have 64/80 (originally 8/10) and 30/80 (originally 3/8). Now which one is the larger number?
64/80 > 30/80
8/10 > 3/8
Answer:
subtraction property of equality
Step-by-step explanation:
First, split this inequality then try each answer.
y>-3x+3y>2x-2
split this into two and simplify each,
y > -3x + 3y -3x+3y > 2x - 2
y - 3y > -3x 3y>2x+3x - 2
-2y > -3x 3y>5x -2
2y<3x
Substituting all the 3 ordered pairs, none of them makes the inequalities true.
