A neutral atom in its ground state contains 28 electrons. this element is considered a <span>transition </span>element, and has 8 electrons in orbitals with l = 2.
Electron configuration: ₂₈X 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸ 4s².
l is azimuthal quantum number, l = 2 describes d orbital. There is eight electrons in 3d orbital.
Answer:
Explanation:
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In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:
Next, we compute the moles of hydrogen that is present at the water only as a product:
Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:
Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:
But the smallest whole number is:
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2.77mg caffeine / 1oz12oz / 1canLethal dose: 10.0g caffeine = 10,000mg caffeine First, find how much caffeine is in one can of soda, then divide that amount by the lethal dose to find the number of cans. (2.77mg caffeine / 1oz) * (12oz / 1can) = 33.24mg caffeine / 1can. (10,000mg caffeine) * (1can / 33.24mg caffeine) = 300.84 cans. Since we can't buy parts of a can of soda, then we have to round up to 301 cans. Notice how all the values were set up as ratios and how the units cancelled.