Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen
if it occupies 31.6 mL at
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.

Temperature = 
As molar mass of
is 32 g/mol. Hence, the number of moles of
are calculated as follows.

Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen
if it occupies 31.6 mL at
.
Kr look on periodic table it's krypton elements
(1) 25 ml of water at 95 degrees Celsius is your answer. Temperature is the average kinetic energy of the substance that it measures, therefore the highest temperature choice, aka #1, is your answer.
Two lobes.
The shape of four sp3 hybrid orbitals is part s and part p-each has two lobes but one lobe is much bigger (which is the lobe used for bonding)