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babunello [35]
3 years ago
15

Anyone please ??? ASAP 15 points ???

Physics
1 answer:
Fed [463]3 years ago
5 0

Answer:

1) you could put more force behind it. (increase) 2) have another object interact with that object. (increase or decrease) 3) the object could hit a wall and stop or slow down (decrease)

Sorry if wrong

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A body travels a distance of 20m in the 7th second and 24m in the 9th second. How much distance shall it travel in the 15th seco
DaniilM [7]

Answer:

<u>36 m</u>

Explanation:

We can consider this to be an AP.

Then,

  • a₇ = 20
  • a₉ = 24

<u>Subtract a₇ from a₉.</u>

  • a + 8d - a + 6d = 24 - 20
  • 2d = 4
  • d = 2

  • a + 6(2) = 20
  • a = 8

<u>Finding a₁₅</u>

  • a₁₅ = a + 14d
  • a₁₅ = 8 + 14(2)
  • a₁₅ = 8 + 28
  • a₁₅ = <u>36 m</u>
4 0
2 years ago
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Which of the following represents a chemical change? (1 point)
fgiga [73]
Can I see a photo or can you comment the answer choices.
8 0
4 years ago
Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to
stiks02 [169]

Now, there is some information missing to this problem, since generally you will be given a figure to analyze like the one on the attached picture. The whole problem should look something like this:

"Beam AB has a negligible mass and thickness, and supports the 200kg uniform block. It is pinned at A and rests on the top of a post, having a mass of 20 kg and negligible thickness. Determine the two coefficients of static friction at B and at C so that when the magnitude of the applied force is increased to 360 N , the post slips at both B and C simultaneously."

Answer:

\mu_{sB}=0.126

\mu_{sC}=0.168

Explanation:

In order to solve this problem we will need to draw a free body diagram of each of the components of the system (see attached pictures) and analyze each of them. Let's take the free body diagram of the beam, so when analyzing it we get:

Sum of torques:

\sum \tau_{A}=0

N(3m)-W(1.5m)=0

When solving for N we get:

N=\frac{W(1.5m)}{3m}

N=\frac{(1962N)(1.5m)}{3m}

N=981N

Now we can analyze the column. In this case we need to take into account that there will be no P-ycomponent affecting the beam since it's a slider and we'll assume there is no friction between the slider and the column. So when analyzing the column we get the following:

First, the forces in y.

\sum F_{y}=0

-F_{By}+N_{c}=0

F_{By}=N_{c}

Next, the forces in x.

\sum F_{x}=0

-f_{sB}-f_{sC}+P_{x}=0

We can find the x-component of force P like this:

P_{x}=360N(\frac{4}{5})=288N

and finally the torques about C.

\sum \tau_{C}=0

f_{sB}(1.75m)-P_{x}(0.75m)=0

f_{sB}=\frac{288N(0.75m)}{1.75m}

f_{sB}=123.43N

With the static friction force in point B we can find the coefficient of static friction in B:

\mu_{sB}=\frac{f_{sB}}{N}

\mu_{sB}=\frac{123.43N}{981N}

\mu_{sB}=0.126

And now we can find the friction force in C.

f_{sC}=P_{x}-f_{xB}

f_{sC}=288N-123.43N=164.57N

f_{sC}=N_{c}\mu_{sC}

and now we can use this to find static friction coefficient in point C.

\mu_{sC}=\frac{f_{sC}}{N}

\mu_{sC}=\frac{164.57N}{981N}

\mu_{sB}=0.168

3 0
3 years ago
The relationship between energy (E), power (P), and time (t) is
NemiM [27]

Answer:

The avarage power of the body is 96.898 watts.

Explanation:

We must notice that given definition of power implies a constant consumption of energy, so that we should assume that energy consumption is constant. A Calorie is equal to 4186 joules. If we know that E = 2000\,Cal and t = 1\,day, the power of body, measured in watts, is:

P = \frac{(2000\,Cal)\cdot \left(4186\,\frac{J}{Cal} \right)}{(1\,day)\cdot \left(24\,\frac{h}{day} \right)\cdot \left(3600\,\frac{s}{h} \right)}

P = 96.898\,W

The avarage power of the body is 96.898 watts.

3 0
4 years ago
What are the three longest wavelengths for standing waves on a 240-cm-long string that is fixed at both ends?
Irina18 [472]
For a standing wave if both ends are fixed, the wavelength must be such that the length of the string be an exact multiple of a half wavelength.
The longest wavelength must be such that the length of the string must be equal to half a wavelength, and therefore the wavelength must be double the length of the string; That is 240× 2 = 480 cm
The second longest wavelength must be such that the length of the string must be equal to a whole wavelength, so the second longest wavelength must be 240 cm.
The third longest wavelength must be such that the length of the string must be equal to 1.5 times the wavelength, so the wavelength must be 240/1.5 = 160 cm.
5 0
3 years ago
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