1) Let's call
the speed of the southbound boat, and
the speed of the eastbound boat, which is 3 mph faster than the southbound boat. We can write the law of motion for the two boats:
2) After a time
, the two boats are
apart. Using the laws of motion written at step 1, we can write the distance the two boats covered:
The two boats travelled in perpendicular directions. Therefore, we can imagine the distance between them (45 mi) being the hypotenuse of a triangle, of which
and
are the two sides. Therefore, we can use Pythagorean theorem and write:
Solving this, we find two solutions. Discarding the negative solution, we have
, which is the speed of the southbound boat.
the complete question in the attached figure
we have that
d=0.51 mm------------------------- >0.00051 m
v = √(2ad) = √(2 * 1300m/s² * 0.00051 m) = 1.15 m/s initial velocity
a=9.8 m/s²
Then d = v² / 2a = (1.15m/s)² / (2*9.8) m/s² = 0.059 m = 59 mm
the answer is 59 mm
Hello there!
The Centripetal force keeps an object moving in a circle or constant direction at the same speed.
Hope this helps!
Answer:
22 degree
Explanation:
Angle of incidence, i = 30 degree
the refractive index of water with respect to air is 4/3.
As the ray of light travels from rarer medium to denser medium, that mean air to water, the refraction takes place.
According to Snell's law,
Refractive index of water with respect to air = Sin i / Sin r
Where, r be the angle of refraction
4 / 3 = Sin 30 / Sin r
0.75 = 2 Sin r
Sin r = 0.375
r = 22 degree
Thus, the angle of refraction is 22 degree.
It's momentum is twice as much.