Answer:If a wave y(x, t) = (6.0 mm) sin(kx + (600 rad/s)t + Φ) travels along a string, how much time does any given point on the string take to move between displacements y = +2.0 mm and y = -2.0 mm?
Explanation:
Answer:
Explanation:
As the current density is given as
now we have current inside wire given as
Now by Ampere's law we will have
Answer:
a)Change in the speed = 1.41 m/s
b)The final speed will be 3.11 m/s
Explanation:
Given that
Acceleration ,a= 4.7 x 10⁻³ m/s²
a)
We know that
v= u + a t
v=final speed ,u=initial speed
t= time ,a= acceleration
Change in the speed
v- u = a t
t= 5 min = 5 x 60 s = 300 s
v- u = 4.7 x 10⁻³ x 5 x 60 m/s
v-u = 1.41 m/s
Change in the speed = 1.41 m/s
b)
Given that
u= 1.7 m/s
v-u = 1.41 m/s
v= 1.7 + 1.41 m/s
v=3.11 m/s
The final speed will be 3.11 m/s
Answer:
Explanation:
The expression which represent the first diffraction minima by a circular aperture is given by 
--------eqn 1
The angle through which the first minima is diffracted is given by 
---------eqn 2
As 
is very small so we can write 
So from eqn 1 and eqn 2 we can write
--------eqn 3
Here 
is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture
It is given that diameter of circular aperture is 14.7 cm so 
Now putting all these value in eqn 3
Work done = Force X Distance
3 430 000J = Force X 14m
Force = 3 430 000J / 14m
= 245 000 N
Hope this helps!
