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Umnica [9.8K]
3 years ago
15

What best describes the difference between the second sound wave and the first?

Physics
1 answer:
Vikki [24]3 years ago
8 0
Missing an attached sheet with the sound waves. Please add the attached sheet so I can properly help.

Thanks! :D
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Protons and neutrons in an atom are held together by _____.
marysya [2.9K]
Protons and neutrons in an atom are held together by a nuclear energy also called the strong force.
7 0
3 years ago
Describe when the chemical<br> reaction occurs in a dry-cell<br> battery
Step2247 [10]

Answer:

<em>For a dry-cell battery to operate, oxidation will occur from the zinc anode and reduction will take place in the cathode. The most common type of cathode is a carbon graphite. Once reactants have been turned into products, the dry-cell battery will work to produce electricity.</em>

Explanation:

<em>The battery operates through electrochemical reactions called oxidation and reduction. These reactions involve the exchange of electrons between chemical species. If a chemical species loses one or more electrons, this is called oxidation. The opposite process, the gain of electrons, is called reduction.</em>

8 0
2 years ago
A 0.750kg block is attached to a spring with spring constant 13.5N/m . While the block is sitting at rest, a student hits it wit
vazorg [7]

Answer:

A)A=0.075 m

B)v= 0.21 m/s

Explanation:

Given that

m = 0.75 kg

K= 13.5 N

The natural frequency of the block given as

\omega =\sqrt{\dfrac{K}{m}}

The maximum speed v given as

v=\omega A

A=Amplitude

v=\sqrt{\dfrac{K}{m}}\times A

0.32=\sqrt{\dfrac{13.5}{0.75}}\times A

A=0.075 m

A= 0.75 cm

The speed at distance x

v=\omega \sqrt{A^2-x^2}

v=\sqrt{\dfrac{K}{m}}\times \sqrt{A^2-x^2}

v=\sqrt{\dfrac{13.5}{0.75}}\times \sqrt{0.075^2-(0.075\times 0.75)^2}

v= 0.21 m/s

5 0
3 years ago
1. How much force is needed to accelerate a 66 kg skier<br> at 2 m/sec2?
Tju [1.3M]

Answer:

<h2>132 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 66 × 2

We have the final answer as

<h3>132 N</h3>

Hope this helps you

3 0
3 years ago
A force of 1.35 newtons is required to accelerate a book by 1.5 meters/second2 along a frictionless surface. What is the mass of
malfutka [58]

B. seems like the answer, I'm not sure.

3 0
4 years ago
Read 2 more answers
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