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stepan [7]
3 years ago
10

Write an equation of the line that passes through the given point P and has the given slope m.

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

9514 1404 393

Answer:

  y -4 = -1/3(x -9)

Step-by-step explanation:

The point-slope form of the equation for a line is useful for this.

  y -k = m(x -h) . . . . . . . line through point (h, k) with slope m

You are given (h, k) = (9, 4) and m = -1/3. Putting these values into the form gives the equation ...

  y -4 = -1/3(x -9)

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Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ
In-s [12.5K]
PART A

The equation of the parabola in vertex form is given by the formula,

y - k = a {(x - h)}^{2}

where

(h,k)=(1,-2)

is the vertex of the parabola.

We substitute these values to obtain,


y  + 2 = a {(x - 1)}^{2}

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.


6  + 2 = a {(3 - 1)}^{2}


8= a {(2)}^{2}


8=4a


a = 2
Hence the equation of the parabola in vertex form is


y  + 2 = 2 {(x - 1)}^{2}


PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

y  + 2 = 2{(x - 1)}^{2}

This implies that

y + 2 = 2(x - 1)(x - 1)


We expand to obtain,


y + 2 = 2( {x}^{2}  - 2x + 1)


This will give us,


y + 2 = 2 {x}^{2}  - 4x + 2


y =  {x}^{2}  - 4x

This equation is now in the form,

y = a {x}^{2}  + bx + c
where

a=1,b=-4,c=0

This is the standard form
7 0
3 years ago
25 points!!!!!!!!
podryga [215]

Answer:

A is your answer, my guy

Step-by-step explanation:

4x1=4

3x-1=-3

5x1=5

4+(-3)+5=6

6x1=6

8x-1=-8

6x1=6

6+(-8)+6=4

4x1=4

2x-1=-2

6x1=6

4+(-2)+6=8

8 0
3 years ago
Select the correct answer.<br> Which graph best models the inequality?<br> y ≤ -2/5x + 2
vaieri [72.5K]

Answer:

it would look like this

Step-by-step explanation:

4 0
2 years ago
In six years Xavier will be 3 times older than Joanne is today. Joanne is 24. How old is Xavier?
Elza [17]

Answer:

72

Step-by-step explanation:

7 0
3 years ago
If 2x^2-5x+7 is subtracted from x^2+2x-11, what is the leading coefficient?
guajiro [1.7K]

Answer:

-1

Step-by-step explanation:

2x² - 5x + 7 is subtracted <em>from </em>x² + 2x - 11, so

(x² + 2x - 11) - (2x² - 5x + 7)

x² + 2x - 11 - 2x² + 5x -7 (Distribute the negative)

-x² + 7x - 18 (Combine like terms)

The leading coefficient is the coefficient of the first term, so it is -1.

3 0
3 years ago
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