Answer:
Explanation:If 5.51 g of water needs 645 J of energy to warm then 55.1 g of water needs 6450 J of energy to warm.
The rate of effusion of ammonia (NH₃) in the same apparatus is 63.3 cm/min
<h3>Graham's law of diffusion </h3>
This states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass i.e
R ∝ 1/ √M
R₁/R₂ = √(M₂/M₁)
<h3>How to determine the rate of ammonia (NH₃) </h3>
- Rate of HCl (R₁) = 43.2 cm/min
- Molar mass of HCl (M₁) = 1 + 35.5 = 36.5 g/mol
- Molar mass of NH₃ (M₂) = 14 + (3×1) = 17 g/mol
R₁/R₂ = √(M₂/M₁)
43.2 / R₂ = √(17 / 36.5)
Cross multiply
43.2 = R₂ × √(17 / 36.5)
Divide both side by √(17 / 36.5)
R₂ = 43.2 / √(17 / 36.5)
R₂ = 63.3 cm/min
Thus, the rate of effusion of ammonia is 63.3 cm/min
Learn more about Graham's law of diffusion:
brainly.com/question/14004529
The best answer between the two choices would be the first option TRUE because the scientific method is used to do more advance research and investigation on things.
No of moles of Carbon, C = mass/ molar mass.
Molar mass of carbon = 12.0107. We only have to calculate the no of moles
of carbon to obtain carbon's mass. .
From Sucrose chemical formula C12H22O11 we know that there are 12
carbon atoms.
So there are 1.4x10^(20) x12 = 16.8 x 10^20 carbon atoms.
We will use avogardo's number to find out the number of carbon molecules
in the compound.
From Avogadro's no. One mole of any substance equals to 6.022140857
atoms.
So X mole contains 16.8 * 10^(20) carbon atom
(16.8x10^20 carbon atoms)/6.022 x10^23 particles/mol = 0.00279 mols
The molar mass of carbon is 12.0107g/mol so we'll multiply to get the mass:
0.00279 mols x 12 = 0.03348.
Answer:
The correct option is: protons; electrons
Explanation:
The electron transport chain contains a series of biomolecules that are involved in the transfer of electrons by redox reactions.
This process involves the transfer of electrons from an <u>electron donor molecule to an electron acceptor molecule</u>, resulting in the <u>release of energy.</u> Some amount of this energy is then used in <u>pumping the protons across the biological membrane.</u>
