The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
T carboxylic acid is an organic compound. the functional group of carboxylic acid is carboxy. general formula is given as : R - COO⁻.
The reactions are given as follows :
1) the reduction of carboxylic acid into ketone with the organometallic compound is given as follows :
CH₃CH₂COOH + CH₃Li ------> CH₃CH₂COCH₃
2 butanone
2) the reaction of carboxylic acid with SOCl₂ is given as follows :
CH₃CH₂COOH + SOCl₂ -----> CH₃CH₂COCl
3) the reaction of carboxylic acid with CH₃NH₂ is given as follows
CH₃CH₂COOH + CH₃NH₂ -----> CH₃CH₂CONHCH₃
Thus, The product for the following reaction are :
- 2 - butanone
- CH₃CH₂COCl
- CH₃CH₂CONHCH₃
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The correct answer should be
<span>carbon monoxide will be produced
Combustions release heat, they don't absorb it. Oxygen is not necessary as other gasses can also do it, while chlorine is not necessary.</span>
I a chemical reaction, we have the reactants in the left part,followed by an arrow and then the products.
So, the reactants are the two that are in the left part of the equation:
Sodium hydroxide and Hydrochloric acid
Answer: C2H4
Explanation:
The percentage composition of ethanol ( C2H5OH ) consist of 52.2% Carbon, Hydrogen of 13.0 and 34.8% of Oxygen.
The percentage composition of ethane gas (C2H6) consist of 80.0% carbon and 20.0% hydrogen.
The composition of Ethylene Glycols i.e C2H4(OH)2 is Carbon of 39.7%, 9.7% hydrogen and 51.6% oxygen.
The percent composition of c2h4 is 86% carbon, and 14% hydrogen.
From the information given, the substance with the highest percentage of carbon is C2H4
Answer:
The solutions are classified according to their ability to scatter light rays.
We can't just use this property because some true solutions also contain undissolved solute.
Explanation:
Tyndall effect refers to the ability of a solution to scatter light rays. True solutions do not scatter light rays while false solutions scatter light rays.
Colloid particles are not large enough to be seen with naked eyes unlike suspensions. We should not confuse a colloid with a suspension because in a suspension, the dispersed solutes are seen with naked eye.
