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inysia [295]
3 years ago
10

Which is the correct set of products for the acid-base neutralization reaction between sulfuric acid (H2SO4) and potassium hydro

xide (KOH)?
Chemistry
1 answer:
Elis [28]3 years ago
3 0

Answer:

H2O and K2SO4

Explanation:

You might be interested in
The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink
masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

<em>10/100 = 10%</em>

7 0
3 years ago
What does the number of valence electrons determine?
N76 [4]

Valence electrons are the electrons in the outermost shell of an element on the periodic table. Atoms want to be able to have a full outer shell and they can share or trade electrons in order to achieve this. Valence electrons are also super super important in chemical reactions. The number of valence electrons determines what group that specific atom or element is in on the periodic table. This affects the reactivity of the element.

4 0
3 years ago
A solution containing aluminium ions forms a white precipitate when a few drops of dilute sodium hydroxide solution are added to
Otrada [13]

Answer:

See explanation

Explanation:

A word equation tries to depict a chemical reaction in words. Letters rather than only chemical formulas are used to show the reaction equation.

Now we want to write a word equation that shows the reaction of sodium hydroxide solution and aluminium sulphate solution:

Alumunium sulphate + sodium hydroxide ------>Aluminium hydroxide + sodium sulphate

7 0
3 years ago
Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of
lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

U_{2}-U_{1}=Q-W

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

dw=Pdv

The pressure is constant, so:  w=P(v_{2}-v_{1} )=0.5*100*1.5=75\frac{kJ}{kg} (There is a multiplication by 100 due to the conversion of bar to kPa)

So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):

U_{2}-U_{1}=500-(3*75)=275kJ

On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:

P_{1}V_{1}=nRT_{1}

P_{2}V_{2}=nRT_{2}\\V_{2}=2.5V_{1}\\P_{2}=P_{1}\\2.5P_{1}V_{1}=nRT_{2}  

Subtracting the first from the second:

1.5P_{1}V_{1}=nR(T_{2}-T_{1})

Isolating T_{2}:

T_{2}=T_{1}+\frac{1.5P_{1}V_{1}}{nR}

Assuming that it is water steam, n=0.1666 kmol

V_{1}=\frac{nRT_{1}}{P_{1}}=\frac{8.314*0.1666*373.15}{500} =1.034m^{3}

T_{2}=100+\frac{1.5*500*1.034}{0.1666*8.314}=659.76 ºC

7 0
3 years ago
Which we events will happen if more H, and t, are added to this reaction
Pani-rosa [81]

Answer:

its is letter c is your answer

Explanation:

I hope this help

5 0
3 years ago
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