The concentration of propionate ions at equivalent point is 0. 084 M
calculation
write the equation for reaction
HC3H5O2 + KOH → H2O + KC3H5O2
find the moles of KOH used
moles= molarity × volume in liters
volume in liters = 37.48 ml/1000 =0.03718L
molarity = 0.141 M
moles is therefore = 0.141 M x0.03718 = 5.24238 x10^-3 moles
by use of mole ratio between KOH and K3C3H5O2 which is 1:1 the moles of K3C3H5O2 is also = 5.24238 x10^-3 moles
molarity is therefore = number of moles/volume in liters
volume in liters = 25/1000 +37.48/1000=0.06248 L
molarity of propionate ions is therefore = (5.24238 x10^-3) / 0.06248 = 0.084 M
Yes that’s right, but where’s the question then?:)))
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