Answer: check for a change in total mass during a reaction.
According to the law of conservation of mass during a chemical change the total mass of the products remains equal to the total mass of the reactants: there is not change in the total mass.
During nuclear reactions the mass can change due to the huge release of energy which proceeds from mass change, as per the famous equation ΔE =Δm. c^2.
The correct type of heat transfer for A, B, and C are conduction, convection and radiation respectively.
<h3>What is heat transfer?</h3>
Heat transfer is a process in which amount of heat will be transferred from one object to any other object by various means.
- In type A, heat is transferred through conduction process as in this transfer takes place due to direct contact of particles.
- In type B, heat is transferred through the convection process as in that process transfer of heat takes place through the medium.
- In type C, heat transfer done by the radiation as in that transfer through empty space.
Hence at A, B and C heat transfer done through conduction, convection and radiation respectively.
To know more about heat transfer, visit the below link:
brainly.com/question/2341645
#SPJ1
Electromagnetic waves<span> or </span>EM waves<span> are waves that are created as a result of vibrations between an electric field and a magnetic field.</span>
<h3>
Answer:</h3>
0.424 J/g °C
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Chemistry</u>
<u>Thermochemistry</u>
Specific Heat Formula: q = mcΔT
- q is heat (in Joules)
- m is mass (in grams)
- c is specific heat (in J/g °C)
- ΔT is change in temperature
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] m = 38.8 g
[Given] q = 181 J
[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C
[Solve] c
<u>Step 2: Solve for Specific Heat</u>
- Substitute in variables [Specific Heat Formula]: 181 J = (38.8 g)c(11.0 °C)
- Multiply: 181 J = (426.8 g °C)c
- [Division Property of Equality] Isolate <em>c</em>: 0.424086 J/g °C = c
- Rewrite: c = 0.424086 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.424086 J/g °C ≈ 0.424 J/g °C
