The result of multiplying that equation is 70,700.
Answer:
A
Explanation:
3 CARBON ATOMS 8 HYDROGEN
Answer:
24.24 L
Explanation:
Boyle’s law, also called Mariotte’s law, a relation concerning the compression and expansion of a gas at constant temperature.
This empirical relation, formulated by the physicist Robert Boyle in 1662, states that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature; i.e., in equation form, pv = k, a constant.
Real gases obey Boyle’s law at sufficiently low pressures, although the product pv generally decreases slightly at higher pressures, where the gas begins to depart from ideal behaviour.
As, PV = k
P₁ V₁ = P₂ V₂
Given P₁ = 101 KPa
V₁ = 6 L
P₂ = 25 kPa
So, V₂ = P₁ V₁ /P₂ = 101 *6/25 = 24.24 L
Answer:
2 moles of KCl will be produced
Explanation:
Given parameters:
Number of moles of K = 2 moles
Unknown:
Number of moles of KCl produced = ?
Solution:
To solve this problem;
Obtain a balanced chemical equation:
2K + Cl₂ → 2KCl ;
Since K is the limiting reactant, its amount will determine the extent of this reaction.
From the balanced equation;
2 moles of K will produce 2 moles of KCl
Given that 2 moles of K reacted, 2 moles of KCl will be produced
Answer:
Oxygen
Explanation:
If two balloons are filled with hydrogen gas and helium gas respectively, then we want to identify what gas is in each balloon, we have to do so by exposing the both balloons to flame in an oxygen atmosphere.
Hydrogen combines with oxygen in the presence of a flame with quite a loud sound and the flame is sustained but when a flame is brought near helium gas in a balloon, the gas will only make a little sound when exposed to the flame and extinguish the flame.
The reason for the explosion of the gas in the hydrogen balloon is that combustion of hydrogen gas is exothermic. The heating up of surrounding air molecules leads to a sudden explosion.
However, the helium balloon makes a little sound when the balloon is ruptured releasing helium gas which extinguishes the flame.
