A neutralization process is a reaction between an acid and a base which yields a salt and water. From the choices, a neutralization reaction would be: 2 HBr + Ca(OH)2 yields CaBr2 + 2 H2O. Moreover, <span>NH3 + HCl yields NH4Cl is also a neutralization reaction. The complete reaction is actually NH4OH + HCl --> NH4Cl + H2O. NH4OH is the aqueous solution of NH3. This reaction is still a neutralization reaction.
On the other hand, the reaction </span><span>HCl + HBr yields H2 + ClBr is not valid. There is no reaction between HCl and HBr because both are strong acids. They would just dissociate into ions like H+, Cl- and Br-.
The valid reaction that is clearly not a neutralization process is </span><span>H2 + Br2 yields 2 HBr. This is a combination reaction yielding a strong acid HBr.</span>
In Fructose, there are 4 carbon atoms. Fructose is a 5 atom molecule, and one of these is oxygen, therefore, the other 4 are carbon.
In Galactose, there are 6 carbon atoms.
Hope this helps :)
Answer:
22.01J/Kmol
Explanation:
The parameters given in this question are;
Enthalpy (H) = 6.01 kJ/mol.
Number of moles = 1
Entropy change (S) = ?
The formular relationship between entropy and enthalpy is given as;
ΔS=ΔH/T
Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)
ΔS = 6.01/273
ΔS = 0.0220kJ/Kmol
ΔS = 0.02201 * 1000 = 22.01J/Kmol
Answer:
b. ΔS° > 0, ΔH° < 0
Explanation:
According the equation of Gibb's free energy -
∆°G = ∆°H -T∆°S
∆°G = is the change in gibb's free energy
∆°H = is the change in enthalpy
T = temperature
∆°S = is the change in entropy .
And , the sign of the Δ°G , determines whether the reaction is Spontaneous or non - Spontaneous or at equilibrium ,
i.e. ,
if
- Δ°G < 0 , the reaction is Spontaneous
- Δ°G > 0 , the reaction is non - Spontaneous
- Δ°G = 0 , the reaction is at equilibrium
The reaction has the value for ∆°H < 0 i.e. negative, and ∆°S > 0 i.e. , positive
Now ,
∆°G = ∆°H -T∆°S
= ( - ∆°H ) - T( + ∆°S )
= ( - ∆°H ) - T( ∆°S )
∆°G = negative
Hence ,
Δ°G < 0 , the reaction is Spontaneous .
