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olga nikolaevna [1]
2 years ago
5

What are all the intermolecular forces present in a sample of BrF?

Chemistry
1 answer:
yuradex [85]2 years ago
4 0

Answer:

dipole-dipole

Explanation:

Intermolecular forces exists between the molecules of a substance in a particular state of matter.

The type of intermolecular forces present in  a substance is determined by the electronegativity difference between the atoms that compose the substance.

There is a non zero electronegativity difference  between Br and F hence the molecule is polar and the intermolecular forces between the molecules of BrF are dipole-dipole forces.

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The answer would be 0.25 g/mL. 
I determined the density by dividing the mass by the volume which gives you the density. D = mass/volume.
<span>6 g / 24 mL = 0.25 g/mL </span>
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Which statement is not true about constitutional isomers?
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What happens to the number of waves when you decrease the wavelength?
Keith_Richards [23]

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Decreasing the wavelength increases the frequency of a wave and vice versa, as long as the energy of the wave remains constant.

Explanation:

The energy of a wave is given by the formula;

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3 years ago
Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
Shtirlitz [24]

Answer:

(a) pH = -Log (0.1M) = 1

(b) pH = -Log (10^{-13}M) = 13

(c) pH = -Log (3x10^{-3}M) = 2.5

(d) pH = -Log (4.93x10^{-10}M) = 9.3

(e) pH = -Log (5^{-7}M) = 6.3

Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

6 0
3 years ago
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