All categories

3 years ago

Why do electrons keep moving around the nucleus and not away from the atom

1 answer:

7 0

The atom's center, or nucleus, is positively charged and the electrons that whirl around this nucleus are negatively charged, so they attract each other. The reason the force is strong is because the atom is so small. The distance between the nucleus and the electrons is about 1 Angstrom (named after a famous scientist); this is 0.00000001 cm (10-8 cm) or about 4 billionths of an

You might be interested in

Which of the following is most likely to be covalent?<br> MgO <br> CO <br> CaO <br> BaO

Kisachek [45]

Answer:

CaO

Explanation:

CaO is the only compound that is a non-metal and a non-metal. The rest of the compounds are ionic, or metal and non-metal.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathfrak%5Cred%7BQuEsTioN%3A-%7D" id="TexFormula1" title="\huge\mathfrak\red{QuEsTio

sladkih [1.3K]

Explanation:

hope it will help you Mark me as a brilliant

6 0

3 years ago

(6.7*10^3)g/mol*L to kg/mol*dL

vodka [1.7K]

6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)= 0.67

7 0

3 years ago

Read 2 more answers

13) Methane (CH4) combines with oxygen according to the balanced equation below. What is the limiting reactant if 25.0 g of CH4

marissa [1.9K]

Answer:

Limiting reactant: Oxygen $O_2$

Explanation:

First write the balanced chemical equation:

$CH_4 + 2 O_2 \rightarrow CO_2 + 2 H_2O$

$mole=\frac{given\, mass}{molecular\, mass}$

given mass of methane =25g

molecular mass of methane=16g/mol

mole=1.5625mol

given mass of oxygen=50

molar mass of oxygen=32g/mol

mole=1.5625mol

from the above balanced equation it is clearly that,

1 mole of methane needs 2 moles of oxygen for complete reaction

Therefore,

1.5625 moles of methane needs 3.125 moles of oxygen for complete reaction but we have only 1.5625 moles of oxygen,

hence,

oxygen will be the limiting reactant and methane will be the excess reactant

8 0

3 years ago

A solution of permanganate is standardized by titration with oxalic acid, . To react completely with mol of oxalic acid required

Zielflug [23.3K]

Answer:

$M=0.120M$

Explanation:

Hello,

In this case, the undergone chemical reaction is:

$MnO_4^-(aq)+H_2C_2O_4(aq)\rightarrow Mn^{+2}+CO_2$

In such a way, the acidic redox balance turns out:

$(Mn^{+7}O_4)^-+5e^-+8H^+\rightarrow Mn^{+2}+4H_2O\\H_2C_2O_4\rightarrow2CO_2+2H^++2e^-$

Which leads to the total balanced equation as follows:

$2(MnO_4)^-(aq)+6H^+(aq)+5H_2C_2O_4(aq)\rightarrow2Mn^{+2}(aq)+8H_2O(l)+10CO_2(g)$

Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:

$1gH_2C_2O_4*\frac{1molH_2C_2O_4}{90.04gH_2C_2O_4} *\frac{2mol(MnO_4)^-}{5molH_2C_2O_4} =0.00444mol(MnO_4)^-$

Whereby the molality results:

$M=\frac{0.00444mol(MnO_4)^-}{0.03702L} =0.120M$

Remember you can modify the oxalic acid mass as you desire.

Best regards.

5 0

3 years ago