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Monica [59]
3 years ago
10

What phase transitions occur as you uniformly increase the pressure on a gaseous sample of iodine from 0.010 atm at 185 ∘c to 10

0 atm at 185 ∘c?
Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

Answer: The phase transition can take place from gaseous to liquid or from gaseous to solid.

Explanation: From the given data in the question, we are increasing the pressure on the gaseous sample at constant temperature.

As we increase the pressure, the particles of the sample come closer to each other which means that it can convert into either solids or liquids.

Hence, two phase transitions are possible for this condition:

1) From gaseous phase to liquid phase

2) From gaseous phase to Solid phase.

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Why can some metals be extracted from compounds by heating with carbon and why can some not
pentagon [3]

Answer:

Some metals can be extracted from compounds by heating with carbon atom because they are less reactive than carbon and some metals cannot be extracted because they are more reactive than carbon atom.

Explanation: If the metal is less reactive than carbon atom so the carbon atoms make bond with oxide or other atom present with metal and the metal is free from that oxide or that element. But if the reactivity of metal is higher than carbon is unable to remove the oxide or element.

8 0
3 years ago
43 milliliters of water weighs 43 g. what is the density of the water?
Anastaziya [24]

Answer:

\rho =1g/mL

Explanation:

Hello,

In this case, since the density is defined as the ratio between the mass and the volume as shown below:

\rho =\frac{m}{V}

We can compute the density of water for the given 43 g that occupy the volume of 43 mL:

\rho =\frac{43g}{43mL}=1g/mL

Regards.

4 0
3 years ago
The compound H2O is an example of a(n)
SashulF [63]
The answer you are looking for is water.
5 0
3 years ago
Read 2 more answers
What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point
Darya [45]

<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories

<u>Explanation:</u>

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

q=m\times L_{vap}

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

L_{vap} = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

q=10g\times 539Cal/g=5390Cal

Hence, the amount of energy absorbed by water is 5390 Calories

6 0
3 years ago
Question 3 of 10
ikadub [295]

Answer:

salt water 97%

fresh water 1%

frozen 2%

Explanation:

8 0
2 years ago
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