Take a hypothetical sample of exactly 100 grams of the solution.
(16g urea) / (60.06 g urea/mol) = 0.2664 mol urea
((100 g total) - (16g urea)) = 84.0 g H2O = 0.0840 kg H2O
(0.2664 mol) /0.0840 (kg) = 3.17143mol/kg = 3.18m urea
2
I can’t really explain in words so I took a pic of the work I did (Ignore the worksheet and just look at what I wrote to balance the equation.)
Sound is a form of energy is incorrect
Sound is caused by the movement or vibration of matter
Answer:
Fructose
Explanation:
A ketose is a monosaccharide containing one ketone group (RCOR) per molecule.
This means to identify a ketose, one has to look for the ketone group in the structural formuar of the compound.
Mannose - This is an aldose. It contains the aldehyde functional group.
Galactose - This is an aldose. It contains the aldehyde functional group.
Fructose - This is a keose. It contains the Ketone Functional group.
Glucose - This is an aldose. It contains the aldehyde functional group.
1 can of soda has 12 ounces * 2.01 mg/oz = 24.12 mg of caffeine.
1 gram = 1000 mg
10 grams x 1000 mg = 10,000 mg
Divide total mg by mg per can:
10,000 / 24.12 = 414.59 cans
Round to 415 cans
