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3 years ago

As temperature decreases a batteries availability power what

1 answer:

7 0

The answer is increases because when something like that decreases it’s always decreasing that probly makes no sense Imao but it’s increases

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As cylinder pressure and heat increase due to an increased load condition, the fuel injection management system must ___________

Temka [501]

possible Answers:

Compensate ⭐⭐⭐⭐⭐

Adjust ⭐⭐⭐⭐⭐

regulate ⭐⭐⭐⭐

tune ⭐⭐⭐

calibrate ⭐⭐⭐

balance ⭐⭐

correct ⭐

6 0

2 years ago

A vertical piston-cylinder device initially contains 0.2 m3 of air at 20°C. The mass of the piston is such that it maintains a c

Ann [662]

Answer:

Amount of air left in the cylinder=m $_{2}$ =0.357 Kg

The amount of heat transfer=Q=0

Explanation:

Given

Initial pressure=P1=300 KPa

Initial volume=V1=0.2 $m^{3}$

Initial temperature=T $_{1}$ =20 C

Final Volume= $V_{2}$ =0.1 $m^{3}$

Using gas equation

$m_{1}=((P_{1}*V_{1})/(R*T_{1}))$

m1==(300*0.2)/(.287*293)

m1=0.714 Kg

Similarly

m2=(P2*V2)/R*T2

m2=(300*0.1)/(0.287*293)

m2=0.357 Kg

Now calculate mass of air left,where me is the mass of air left.

me=m2-m1

me=0.715-0.357

mass of air left=me=0.357 Kg

To find heat transfer we need to apply energy balance equation.

$Q=(m_{e}*h_{e})+(m_{2}*h_{2})-(m_{1}*h_{1})$

Where me=m1-m2

And as the temperature remains constant,hence the enthalpy also remains constant.

h1=h2=he=h

Q=(me-(m1-m2))*h

me=m1-me

Thus heat transfer=Q=0

6 0

3 years ago

The 10-lb block is pressed against the spring so as to compress it 2 ft when it is at a point A. If the plane is smooth, determi

leva [86]

Answer:

The distance measure from the wall = 36ft

Explanation:

Given Data:

w = 10

g =32.2ft/s²

x = 2

Using the principle of work and energy,

T₁ +∑U₁-₂ = T₂

0 + 1/2kx² -wh = 1/2 w/g V²

Substituting, we have

0 + 1/2 * 100 * 2² - (10 * 3) = 1/2 * (10/32.2)V²

170 = 0.15528V²

V² = 170/0.15528

V² = 1094.796

V = √1094.796

V = 33.09 ft/s

But tan ∅ = 3/4

∅ = tan⁻¹3/4

= 36.87°

From uniform acceleration,

S = S₀ + ut + 1/2gt²

It can be written as

S = S₀ + Vsin∅*t + 1/2gt²

Substituting, we have

0 = 3 + 33.09 * sin 36.87 * t -(1/2 * 32.2 *t²)

19.85t - 16.1t² + 3 = 0

16.1t² - 19.85t - 3 = 0

Solving it quadratically, we obtain t = 1.36s

The distance measure from the wall is given by the formula

d = VCos∅*t

Substituting, we have

d = 33.09 * cos 36. 87 * 1.36

d = 36ft

5 0

3 years ago

Read 2 more answers

Jelena is 26 and has worked in the service industry for most of her work history. She is willing to advance her education and tr

katrin2010 [14]

Customer service

Since she has reckless driving and her record, anything involving driving of some sorts mechanics as well won’t work well with her!! Hope this helps

8 0

3 years ago

An air-conditioner with refrigerant-134a as the working fluid is used to keep a room at 23°C by rejecting the waste heat to the

Kryger [21]

Answer:

(a) 3.455

(b) 21.143

Explanation:

In this question, we’d be providing solution to the working process of a refrigerator given the data in the question.

Please check attachment for complete solution and step by step explanation

7 0

3 years ago