The answer c for your question
Answer:
a) 3.0 x 10¹⁰ J
b) 7.75 x 10³ m/s
Explanation:
a)
ΔV = potential difference between cloud and the ground = 1.0 x 10⁹ Volts
Q = Amount of charge transferred = 30 C
ΔU = Change in energy transferred
Change in energy transferred is given as
ΔU = Q ΔV
ΔU = (30) (1.0 x 10⁹)
ΔU = 3.0 x 10¹⁰ J
b)
v₀ = initial speed of the automobile = 0 m/s
v = final speed of the automobile = ?
m = mass of automobile = 1000 kg
Using conservation of energy
ΔU = (0.5) m (v² - v₀²)
3.0 x 10¹⁰ = (0.5) (1000) (v² - 0²)
v = 7.75 x 10³ m/s
Answer:
26 cm
Explanation:
V = Volume
R = Outer radius of the shell = 58.7 cm
r = Inner radius of the shell
g = Acceleration due to gravity = 9.81 m/s²
\rho = Density
As the shell is completely submerged
Force on shell
Weight of the shell
Equating the two equations as the forces are conserved
Inner radius of the shell is 0.561 m
The thickness of the wall is 0.587-0.561 = 0.026 m = 26 cm