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AURORKA [14]
3 years ago
12

A 1kg pool ball travels to the right at 2m/s and hits another stopped pool ball bounces back to the left at 1m/s what is the vel

ocity of the other pool ball
Physics
1 answer:
Burka [1]3 years ago
5 0
Ptotal=Ptotal —> m1v1+m2v2=m1v1’+m2v2’ —> (1kg)(2m/s)+(1kg)(0m/s)=(1kg)(-1m/s)+(1kg)(v2’) —> v2’=3m/s

answer: v=3m/s
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Only 25% of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric f
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Answer: Only 25% of the intensity of a polarized light wave passes through a polarizing filter. Then the angle between the electric field and the axis of the filter will be 60 degrees.

Explanation: To find the answer of the problem given, we have to know about the Malu's law of polarization.

<h3>What is Malu's law of polarization?</h3>
  • This law states that, when a beam of completely polarized light is passed through an analyzer, then then intensity I of the transmitted light varies directly as the square of the angle \alpha between the transmission direction of the polarizer and the analyzer.
  • The expression for this law will be,

                                         I=I_0cos\alpha

  • Where, I₀ is the maximum intensity of the transmitted light through the polarizer.
<h3>How to solve the problem?</h3>
  • From the question, it is clear that, the 25% of the intensity of a polarized light wave passes through the filter.

                                        \frac{I}{I_0} =0.25\\

  • Thus, the angle between electric field and the axis of the filter is,

                                        cos^2\alpha =0.25\\cos\alpha =\sqrt{0.25} =0.5\\\alpha =cos^-1(0.5)=60 degrees

Thus, we can conclude that, the angle between the electric field and the axis of the filter will be 60 degrees.

Learn more about the Malus law of polarization here:

brainly.com/question/28020002

#SPJ4

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