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uysha [10]
3 years ago
14

If a rhombus is a square, then it is a rectangle ( True or False )

Mathematics
2 answers:
grigory [225]3 years ago
7 0

Answer:

That would be false

Step-by-step explanation:

nirvana33 [79]3 years ago
6 0
False i believeeee :p
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How do you get an equation to solve for all 3 sides of a triangle?
slavikrds [6]

In your solving toolbox (along with your pen, paper and calculator) you have these 3 equations:

1. The angles always add to 180°:

A + B + C = 180°

When you know two angles you can find the third.

 

2. Law of Sines (the Sine Rule):

Law of Sines

When there is an angle opposite a side, this equation comes to the rescue.

Note: angle A is opposite side a, B is opposite b, and C is opposite c.

 

3. Law of Cosines (the Cosine Rule):

Law of Cosines

This is the hardest to use (and remember) but it is sometimes needed  

to get you out of difficult situations.

It is an enhanced version of the Pythagoras Theorem that works  

on any triangle.

With those three equations you can solve any triangle (if it can be solved at all).

Six Different Types (More Detail)

There are SIX different types of puzzles you may need to solve. Get familiar with them:

1. AAA:

This means we are given all three angles of a triangle, but no sides.

AAA Triangle

AAA triangles are impossible to solve further since there are is nothing to show us size ... we know the shape but not how big it is.

We need to know at least one side to go further. See Solving "AAA" Triangles .

 

2. AAS

This mean we are given two angles of a triangle and one side, which is not the side adjacent to the two given angles.

AAS Triangle

Such a triangle can be solved by using Angles of a Triangle to find the other angle, and The Law of Sines to find each of the other two sides. See Solving "AAS" Triangles.

 

3. ASA

This means we are given two angles of a triangle and one side, which is the side adjacent to the two given angles.

ASA Triangle

In this case we find the third angle by using Angles of a Triangle, then use The Law of Sines to find each of the other two sides. See Solving "ASA" Triangles .

 

4. SAS

This means we are given two sides and the included angle.

SAS Triangle

For this type of triangle, we must use The Law of Cosines first to calculate the third side of the triangle; then we can use The Law of Sines to find one of the other two angles, and finally use Angles of a Triangle to find the last angle. See Solving "SAS" Triangles .

 

5. SSA

This means we are given two sides and one angle that is not the included angle.

SSA Triangle

In this case, use The Law of Sines first to find either one of the other two angles, then use Angles of a Triangle to find the third angle, then The Law of Sines again to find the final side. See Solving "SSA" Triangles .

 

6. SSS

This means we are given all three sides of a triangle, but no angles.

SSS Triangle

In this case, we have no choice. We must use The Law of Cosines first to find any one of the three angles, then we can use The Law of Sines (or use The Law of Cosines again) to find a second angle, and finally Angles of a Triangle to find the third angle.

7 0
3 years ago
Read 2 more answers
As a computer programmer, you have to define the movements of a battleship across a virtual grid . Will you program the transfor
n200080 [17]
I took this test the other day I put figure 2 and I got it right
3 0
3 years ago
I need help with this please help me
AveGali [126]
Sorry i cant help you sorry
3 0
3 years ago
Krystal’s poster project for reading class is 2 feet high and 1 1 2 feet wide. Her friend Victoria’s poster is 4 feet high and 1
Bess [88]

The area of Victoria's poster is twice the area of Krystal's poster.

<h3>How compare the areas of two similar posters</h3>

The two areas are shown in the image attached below. Each poster represents a rectangle and the ratio between the two areas (r_{A}), no unit, is defined by the following formula:

r_{A} = \frac{w_{V}\cdot h_{V}}{w_{K}\cdot h_{K}}     (1)

Where:

  • w_{V} - Width of Victoria's poster, in feet.
  • h_{V} - Height of Victoria's poster, in feet.
  • w_{K} - Width of Krystal's poster, in feet.
  • h_{K} - Height of Krystal's poster, in feet.

If we know that h_{V} = 4\,ft, w_{V} = 1.5\,ft, h_{K} = 2\,ft and w_{K} = 1.5\,ft, then the ratio between the two areas is:

r_{A} = \frac{(4)\cdot (1.5)}{(2)\cdot (1.5)}

r_{A} = 2

The area of Victoria's poster is twice the area of Krystal's poster. \blacksquare

To learn more on ratios, we kindly invite to check this verified question: brainly.com/question/1504221

5 0
2 years ago
Plz help will choose brainliest!
Allisa [31]

Answer:

D, E, F

Step-by-step explanation:

The first step I would do is distribute the original equation. After distributing, the equation is now 8x² + 16xy. The first answer I see that matches this is D.

Then, after already eliminating A, B, and C, I look at E. I distribute the x and find out it is also equal to 8x² + 16xy.

Then, I look at F. After distributing again, it is also equal to 8x² + 16xy.

3 0
3 years ago
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