!!!!!!HELP PLEASE!!!!!!!! #9 and #10 are the questions i need answered
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If you were to compute this, Angle C should be equal to 100°.
In a triangle, all angles sum up to 180°.
In triangle ABC, where the m∠A =30° and m∠50°:
m∠A + m∠B + m∠C = 180°
30° + 50 + m∠C = 180°
80° + m∠C = 180°
m∠C = 180° - 80°
m∠C = 100°
The triangle should look like the picture attached.
In a triangle, all angles sum up to 180°.
In triangle ABC, where the m∠A =30° and m∠50°:
m∠A + m∠B + m∠C = 180°
30° + 50 + m∠C = 180°
80° + m∠C = 180°
m∠C = 180° - 80°
m∠C = 100°
The triangle should look like the picture attached.