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yulyashka [42]
2 years ago
10

Determine the empirical formula of a compound containing 8.56 g silicone of 43.2 g of chlorine

Chemistry
1 answer:
SpyIntel [72]2 years ago
6 0

The empirical formula of the compound is SiCl₄.

<h3>Empirical formula of the compound</h3>

mass of silicon = 28 g/mol

mass of chlorine = 35.5 g/mol

<h3>molar ration: </h3>

Si = 8.56/28   =  0.306

Cl = 43.2/35.5  = 1.216

<h3>Combining ratio</h3>

Si = 0.306/0.306 = 1

Cl = 1.216/0.306 = 4

empirical formula = SiCl₄

Thus, the empirical formula of the compound is SiCl₄.

Learn more about empirical formula here: brainly.com/question/1603500

#SPJ1    

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Predict the missing product of this equation<br><br><br>1 MgF2 + 1 Li2CO3 -&gt; 1 ______ +2LiF
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Answer:

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Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

MgF₂ (aq) —> Mg²⁺ + 2F¯

Li₂CO₃ (aq) —> 2Li⁺ + CO₃²¯

MgF₂ + Li₂CO₃ —>

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MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Therefore, the missing part of the equation is MgCO₃

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