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REY [17]
3 years ago
7

Scientists conducting a study on global climate change want to determine if there has been an increase in the number of days per

year that the temperature in El Paso rises above 100 degrees. In 1981, there were 21 days (5.75%) where the temperature was in the triple digits. The scientists want to know whether this percentage has increased. Which pairs of hypotheses is the most appropriate for addressing this question?
Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

The percentage maybe went up because of air pollution, and global warming

Step-by-step explanation:

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What does ECONOMY MEAN PLZ TELL ME
ratelena [41]
<span>The wealth and resources of a country or region, especially in terms of the production and consumption of goods and services.

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</span><span>Careful management of available resources.</span>
6 0
2 years ago
Read 2 more answers
Bee + ant= 10, ant - bee = 8, ant × bee= ?
Alona [7]

The Correct Answer Is...

<em><u>9.</u></em>

Any Questions? Comment Below!

<em><u>-AnonymousGiantsFan</u></em>

7 0
3 years ago
I need your help if the airplane was at altitude of 800 feet above sea level. It landed at airport 45 feet below sea level. Whic
kipiarov [429]

Answer:

800 ft above sea level

Step-by-step explanation:

6 0
3 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
3 years ago
How many multiples of three are between 10 and 787 and show work pls
SOVA2 [1]
787-10=777
777/3=259

259 multiples of 3
8 0
3 years ago
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