Consider the closed region

bounded simultaneously by the paraboloid and plane, jointly denoted

. By the divergence theorem,

And since we have

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have




Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by

, we have

Parameterize

by


which would give a unit normal vector of

. However, the divergence theorem requires that the closed surface

be oriented with outward-pointing normal vectors, which means we should instead use

.
Now,



So, the flux over the paraboloid alone is
#1
The ALTITUDE is
a line segment that connects a vertex of a triangle to a point on the
line containing the opposite side, so that the line segment is perpendicular to that line.
#2
The MEDIAN a line segment that connects a vertex of a triangle to the midpoint of the opposite side
The formula for this ( horizontal circular orbit with the origin at the center) is
L = mvr
Answer:
b)-1/2 is the required answer
Step-by-step explanation:


It might be 2/9 sorry if it wasn’t