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stepan [7]
3 years ago
11

A necklace is being made with beads that are each 1.25 centimeters in diameter. How many beads does it take to make a necklace t

hat is 30 centimeters long
Mathematics
1 answer:
Oliga [24]3 years ago
3 0

Answer: $3.60 will be spent on the necklace.

Step-by-step explanation:

to solve this problem we have to divide the length of the necklace (30cm ) by the diameter of each bead (1.25) to obtain the number of beads needed for the necklace.

So, mathematically speaking:

30 cm / 1.25 cm =24 beads

Now, we have to multiply the number of beads by the cost of each one ($0.15).

24 x 0.15=  $3.60

S000, $3.60 will be spent on the necklace.

- Katsuki Bakugou

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PLEASE HELP! <br><br>Identify the y-intercept and zeros of <br>y = x^4 - 9x^2 - 36<br>Algebraically​
const2013 [10]

Answer:

Our y-intercept is (0, -36).

Our real zeros are: (-2√3, 0) and (2√3, 0)

And our imaginary zeros are: (i√3, 0) and (-i√3, 0)

Step-by-step explanation:

We have the function:

y=x^4-9x^2-36

Let's identify the y- and x-intercepts.

Y-Intercept:

To determine the y-intercept, we will substitute 0 for x and solve for y. So:

y=(0)^4-9(0)^2-36

Evaluate:

y=-36

Therefore, our y-intercept is at (0, -36).

X-Intercepts:

To determine our x-intercepts, we need to substitute 0 for y and solve for x. So:

0=x^4-9x^2-36

Now, we can factor. Before doing so, we can make the factored easier to see by converting this into quadratic form. Let's let u=x². Then:

0=(u^2)^2-9(x^2)-36

Substitute:

0=u^2-9u-36

Now, let's factor. We can use -12 and 3. So:

0=u^2+3u-12u-36 \\ 0=(u(u+3)-12(u+3)) \\ 0=(u-12)(u+3)

Now, we can substitute back u:

0=(x^2-12)(x^2+3)

Zero Product Property:

x^2-12=0\text{ or } x^2+3=0

Solve for x in each case:

x^2=12 \text{ or } x^2=-3

Take the square root of both sides. Since we're taking an even root, we will need plus/minus. Therefore:

x=\pm\sqrt{12}=\pm2\sqrt{3}\text{ or } x=\pm\sqrt{-3}=\pm i\sqrt{3}

Therefore, our zeros (both real and imaginary) are: (2√3, 0), (-2√3, 0), (i√3, 0), and (-i√3, 0)

5 0
3 years ago
Determine the value of k for which -3x^2+12x+k=0 has no real roots. ​
Crazy boy [7]

Answer:

K<-12

Step-by-step explanation:

+ For that, we need the delta negatif.

+ The delta= b^2-4ac=12^2-4(-3)(k)=144+12k<0

Then, 12k<-144 (divise both sides by 12)

we have k<-12

Or an other way:

-3x^2+12x+k=0  (divise both sides by -3)

x^2-4x-k/3=0

x^2-4x+4 -4-k/3=0

(x-2)^2=4+k/3

Now , we need 4+k/3<0, k/3<-4 or k<-12

Hope you understand.

4 0
3 years ago
Help me I only have until 8:50 to finish this please help me​
lianna [129]

1a) f(4) = 2

1b) x = 1 and x = 3

2a) g(3) = 55

2b) If you work 5 hours... you could expect to earn $85 (according to the function)

6 0
3 years ago
−5x+2y=9<br> y=7x<br> ​x=<br> y=
Serhud [2]

- 5x+2y=9 \\ y=7x

We know that y=7x, so we just need tu put it into the 1st equation

- 5x + 2 \times 7x = 9 \\  - 5x + 14x = 9 \\ 9x = 9 | \div 9 \\ 9x \div 9 = 9 \div 9 \\ x = 1

So we found x. Now we can find y

y = 7 \times 1 \\ y = 7

Answer:

x=1, y=7; or (1;7)

4 0
3 years ago
SM=3x−4, and RN=9x−20. Find the value of x
Rudik [331]

Answer:

Option (A).

Step-by-step explanation:

Given question is incomplete; find the complete question with the attachment.

In the triangle NRL,

Points P, S and M are the midpoints of the sides NR, RL and LN respectively.

Sides SM = (3x - 4), NR = (9x - 20)

By the theorem of midpoints in a triangle,

SM = \frac{1}{2}\text{NR}

(3x - 4) = \frac{1}{2}(9x-20)

6x - 8 = 9x - 20

9x - 6x = 20 - 8

3x = 12

x = 4

Therefore, Option (A) will be the answer.

8 0
3 years ago
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