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2 years ago

How many moles are in 43.5 g of sodium hydroxide (NaOH)?

Chemistry

1 answer:

Makovka662 [10]2 years ago

3 0

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

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The reaction NO2(g) + CO(g) → NO(g) + CO2(g) has been found to be second order with respect to NO2 and zero order with respect t

hodyreva [135]

Answer:

The answer is " $122.88 \times 10^{-5}$ "

Explanation:

In the given question some data is missing. so, the correct solution can be defined as follows:

Missing values:

$k= 3.0 \times 10^{-5}\\\\NO_2 =6.4 \ mol / l \\\\CO= 4.1 mol / l \\\\NO= 5.2 mol / l \\\\CO_2= 1.3 mol / l\\$

Given equation:

$NO_2(g) + CO(g) \longrightarrow NO(g) + CO_2(g)$

In the above equation, the rate is $=k.[NO_2]^2$ because the above given is the part of the second-order, which relates to $NO_2$ . In the zeros order the Carbon monoxide (CO) its reaction doesn't affect the rate.

Calculating the rate:

Rate $=k.[NO_2]^2$

$= 3.0 \times 10^{-5} \times 6.4^2\\\\=3.0 \times 10^{-5} \times 40.96\\\\= 122.88 \times 10^{-5}\\$

7 0

2 years ago

Calculate the volume in milliliters of a 1.3M zinc nitrate solution that contains 100.g of zinc nitrate ZnNO32. Be sure your ans

zheka24 [161]

Answer:

The volume is 406 mL

Explanation:

Step 1: Data given

Molarity of a zinc nitrate solution = 1.3 M

Mass of zinc nitrate = 100 grams

Molar mass of Zn(NO3)2 = 189.36 g/mol

Step 2: Calculate moles Zn(NO3)2

Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2

Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol

Moles Zn(NO3)2 = 0.5281 moles

Step 3: Calculate volume

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.5281 moles / 1.3 M

Volume = 0.406 L = 406 mL

The volume is 406 mL

3 0

3 years ago

How many molecules of N2 are in a 400.0 mL container at 780 mm Hg and 135°C? Avogadro’s number = 6.022 x 1023A) 7.01 × 1021 mole

ASHA 777 [7]

Answer:

Explanation:

Firstly, we will need to calculate the number of moles. To do this, we make use of the ideal gas equation

PV = nRT

n = PV/RT

The parameters have the following values according to the question:

P = 780mmHg, we convert this to pascal.

760mHG = 101325pa

780mmHg = xpa

x = (780 * 101325)/760 = 103,991 Pa

V= 400ml = 0.4L

T = 135C = 135 + 273.15 = 408.15K

n = ?

R = 8314.463LPa/K.mol

Substituting these values into the equation yields the following:

n = (103991 * 0.4)/(8314.463 * 408.15)

= 0.012 moles

Now we know 1 mole contains 6.02 * 10^23 molecules, hence, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecules

8 0

2 years ago

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How do the scientist know that cells exist

IrinaVladis [17]

Because of us and other cells from plants and Animals

7 0

2 years ago

HELP ASAPPPP

Cloud [144]

Answer:

13 years

Explanation:

From;

0.693/t1/2 = 2.303/t log (No/N)

Where;

t1/12 = half-life of Cobalt-60 = 5.3 years

t = time taken = the unknown

No = mass of radioactive material originally present = 5.2 g

N = mass of radioactive material at time t = 0.95 g

Substituting values;

0.693/5.3 = 2.303/t log (5.2/0.95)

0.131 = 2.303/t(0.738)

0.131 = 1.6996/t

t = 1.6996/0.131

t = 12.97 years

t = 13 years(to the nearest whole number)

3 0

2 years ago