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Travka [436]
3 years ago
5

How many moles are in 43.5 g of sodium hydroxide (NaOH)?

Chemistry
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

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0.254g lead(ii)ethanoate, on adding excess K2CrO4 solution, gave 0.130g of lead(ii)chromate precipitate. what is the percentage
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Explanation:

All of the Pb⁺² species precipitated as lead(II) cromate, PbCrO₄ (we know this as excess K₂CrO₄ was used).

First we convert 0.130 g of PbCrO₄ into moles, using its molar mass:

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