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Travka [436]
3 years ago
5

How many moles are in 43.5 g of sodium hydroxide (NaOH)?

Chemistry
1 answer:
Makovka662 [10]3 years ago
3 0

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

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The equilibrium will shift to the right

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In this case:

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According to the Le Chatelier principle, the addition of NaOH consumes one of the products, decreasing its concentration. Therefore, to balance the reaction, <u><em>the equilibrium will shift to the right</em></u> in order to counteract the effect that disturbed it and recover the equilibrium state.

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Using the table on the right, complete each unit conversion by typing in the correct answer. 85.0 kg =_____ lb​
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Assuming the boiling point increased by 2 °C, what is the approximate molality of NaCl when the video ends? Kbp(water) = 0.512
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Explanation :

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\Delta T_b=i\times k_b\times m

where,

\Delta T_b = change in boiling point = 2^oC

k_b = boiling point constant  for water = 0.512^oC/m

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i = Van't Hoff factor = 2 (for electrolyte)

The dissociation NaCl will be,

NaCl\rightarrow Na^++Cl^{-}

So, Van't Hoff factor = Number of solute particles = Na^++Cl^{-} = 1 + 1 = 2

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