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2 years ago

Which discipline of Earth and space science is concerned with the study of the planets and stars?

Chemistry

1 answer:

sweet-ann [11.9K]2 years ago

7 0

Answer:

The discipline of Earth and space science is concerned with the study of the planets and stars is

A. Astronomy

Explanation:

A.Astronomy:

'Astron' means stars and 'nomos' means laws. So astronomy is the study of stars , planets and space

B. biology

It is derived from Greek word : 'Bios' means life and 'logos' means study.

Biology is study of life, living organism ,structure of organisms,evolution

C.Geology

It is the earth science which includes the study of rocks and solid earth, what it is made of and how it has changed .

D. Oceanography

It is the study of physical and biological aspects of oceans

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Compute the percent ionic character of the interatomic bonds for the following compounds : a. TiO2 b. ZnTe c. CsCld. InSb e. MgC

sesenic [268]

Answer:

a. 63.2%

b. 11.7%

c. 73.3%

d. 0.995%

e. 55.5%

Explanation:

An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).

The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:

$%IC = (1 - e^{-0.25*(x_A - x_B)^2})$ *100%

Where $x_A - x_B$ is the electronegativity difference of the elements. Thus, consulting an electronegativity table:

a. $x_{Ti}$ = 1.5

$x_{O}$ = 3.5

$%IC = (1 - e^{-0.25*(3.5 - 1.5)^2})$ *100%

%IC = 63.2%

b. $x_{Zn}$ = 1.6

$x_{Te}$ = 2.1

$%IC = (1 - e^{-0.25*(2.1 - 1.6)^2})$ *100%

%IC = 11.7%

c. $x_{Cs}$ = 0.7

$x_{Cl}$ = 3.0

$%IC = (1 - e^{-0.25*(3.0 - 0.7)^2})$ *100%

%IC = 73.3%

d. $x_{In}$ = 1.7

$x_{Sb}$ = 1.9

$%IC = (1 - e^{-0.25*(1.9 - 1.7)^2})$ *100%

%IC = 0.995 %

e. $x_{Mg}$ = 1.2

$x_{Cl}$ = 3.0

$%IC = (1 - e^{-0.25*(3.0 - 1.2)^2})$ *100%

%IC = 55.5%

4 0

2 years ago

Complete this sentence. If mass remains the same while the volume of a substance ________, the density of the substance will____

VARVARA [1.3K]

Answer:

B. Increases, Decreases

Explanation:

I majored in Chemistry

4 0

2 years ago

Calculate the ph of a 0.005 m solution of potassium oxide k2o

Alecsey [184]

First, we have to see how K2O behaves when it is dissolved in water:

K2O + H20 = 2 KOH

According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:

c(KOH) : c(K2O) = 1 : 2

So,

c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)

Now we can calculate pH:

pOH= -log c(OH⁻) = -log 0.01 = 2

pH= 14-2 = 12

3 0

2 years ago

Heating up a reaction increases the speed of a reaction until the ____

Vesnalui [34]

Heating up a reaction increases the speed of a reaction until the enzyme denatures.

<h3>What is enzyme denaturation?</h3>

Enzyme denaturation occurs when a biological protein catalyst does not work anymore due to a high temperature that alters its tridimensional conformation.

This cellular process (denaturation) is well known to be one of the main causes of enzymatic failure.

In conclusion, heating up a reaction increases the speed of a reaction until the enzyme denatures.

Learn more about enzymes here:

brainly.com/question/1596855

#SPJ12

5 0

1 year ago

What is the final pressure (expressed in atm) of a 3.05 L system initially at 724 mm Hg and 298 K, that is compressed to a final

maksim [4K]

Hey there!:

V1 = 3.05 L

V2 = 3.00 L

P1 = 724 mmHg

P2 = to be calculated

T1 = 298 K

T2 = 273 K

Therefore:

P1*V1 / T1 = P2*V2 / T2

P2 = ( P1*V1 / T1 ) * T2 / V2

P2 = 724 * 3.05 * 273 / 298 * 3.00

P2 = 602838.6 / 894

P2 = 674.31 mmHg

1 atm ----------- 760 mmHg

atm ------------- 674.31 mHg

= 674.31 * 1 / 760

= 0.887 atm

Hope this helps!

5 0

3 years ago