1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesya [120]
3 years ago
8

Which discipline of Earth and space science is concerned with the study of the planets and stars?

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

The discipline of Earth and space science is concerned with the study of the planets and stars is

A. Astronomy

Explanation:

A.Astronomy:

'Astron' means stars and 'nomos' means laws. So astronomy is the study of stars , planets and space

B. biology

It is derived from Greek word : 'Bios' means life and 'logos' means study.

Biology is study of life, living organism ,structure of organisms,evolution

C.Geology

It is the earth science which includes the study of rocks and solid earth, what it is made of and how it has changed .

D. Oceanography

It is the study of physical and biological aspects of oceans

You might be interested in
What is a particle diagram to illustrate the composition of air
navik [9.2K]
A diagram of the composition of air would be the air's chemical formula and it's structure. 
4 0
3 years ago
Which element has the greatest electronegativity? B C Cl
mihalych1998 [28]
Chlorine. Electronegativity rises as you go up and to the right on the periodic table.
3 0
3 years ago
A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa
timofeeve [1]
The answer you are looking for would be a colliod. Hope this helps have a great day!!

6 0
3 years ago
Read 2 more answers
20cm of 0.09M solution of H2SO4. requires 30cm of NaOH for complete neutralization. Calculate the
kirill115 [55]

Answer:

Choice A: approximately 0.12\; \rm M.

Explanation:

Note that the unit of concentration, \rm M, typically refers to moles per liter (that is: 1\; \rm M = 1\; \rm mol\cdot L^{-1}.)

On the other hand, the volume of the two solutions in this question are apparently given in \rm cm^3, which is the same as \rm mL (that is: 1\; \rm cm^{3} = 1\; \rm mL.) Convert the unit of volume to liters:

  • V(\mathrm{H_2SO_4}) = 20\; \rm cm^{3} = 20 \times 10^{-3}\; \rm L = 0.02\; \rm L.
  • V(\mathrm{NaOH}) = 30\; \rm cm^{3} = 30 \times 10^{-3}\; \rm L = 0.03\; \rm L.

Calculate the number of moles of \rm H_2SO_4 formula units in that 0.02\; \rm L of the 0.09\; \rm M solution:

\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V(\mathrm{H_2SO_4})\\ &= 0.02 \; \rm L \times 0.09 \; \rm mol\cdot L^{-1} = 0.0018\; \rm mol \end{aligned}.

Note that \rm H_2SO_4 (sulfuric acid) is a diprotic acid. When one mole of \rm H_2SO_4 completely dissolves in water, two moles of \rm H^{+} ions will be released.

On the other hand, \rm NaOH (sodium hydroxide) is a monoprotic base. When one mole of \rm NaOH formula units completely dissolve in water, only one mole of \rm OH^{-} ions will be released.

\rm H^{+} ions and \rm OH^{-} ions neutralize each other at a one-to-one ratio. Therefore, when one mole of the diprotic acid \rm H_2SO_4 dissolves in water completely, it will take two moles of \rm OH^{-} to neutralize that two moles of \rm H^{+} produced. On the other hand, two moles formula units of the monoprotic base \rm NaOH will be required to produce that two moles of \rm OH^{-}. Therefore, \rm NaOH and \rm H_2SO_4 formula units would neutralize each other at a two-to-one ratio.

\rm H_2SO_4 + 2\; NaOH \to Na_2SO_4 + 2\; H_2O.

\displaystyle \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})} = \frac{2}{1} = 2.

Previous calculations show that 0.0018\; \rm mol of \rm H_2SO_4 was produced. Calculate the number of moles of \rm NaOH formula units required to neutralize that

\begin{aligned}n(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{n(\mathrm{H_2SO_4})}\cdot n(\mathrm{H_2SO_4}) \\&= 2 \times 0.0018\; \rm mol = 0.0036\; \rm mol\end{aligned}.

Calculate the concentration of a 0.03\; \rm L solution that contains exactly 0.0036\; \rm mol of \rm NaOH formula units:

\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} = \frac{0.0036\; \rm mol}{0.03\; \rm L} = 0.12\; \rm mol \cdot L^{-1}\end{aligned}.

3 0
3 years ago
Which indicator would show a pH change from 6 to 7?
tatyana61 [14]

Answer:

c

Explanation:

1. litmus paper is used when showing a change between a greater range in ph levels - so A and D are automatically a no.

2. methyl red is used to show a range in ph levels between 4.8-6

3. Option C is the only one left so im going to assume its C because its definitely not A, B, or D

7 0
2 years ago
Other questions:
  • Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11
    7·1 answer
  • Show that the Joule-Thompson Coefficient is zero for ideal gas.
    11·1 answer
  • The Hot-Wheel car was accelerating across the table at 0.25 meters per second squared (m/s^2) from an applied force of 10 N. Wha
    11·1 answer
  • Which section of the reaction represents the products?<br> A) a <br> B) b <br> C) c <br> D) d
    15·2 answers
  • Which of these is NOT a colloid?
    8·1 answer
  • ¿Cómo se llama el proceso en donde se transforma el oxígeno en dióxido de carbono
    11·1 answer
  • A. Stamens (p) The portion of the pistil receiving the pollen
    6·2 answers
  • In any food web, the organisms that are responsible for converting raw energy into usable chemical energy are collectively calle
    9·2 answers
  • True or False - Changing the temperature will not affect the pressure of the mixture?
    6·2 answers
  • Gas Law- please help!!!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!