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lesya [120]
3 years ago
8

Which discipline of Earth and space science is concerned with the study of the planets and stars?

Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
7 0

Answer:

The discipline of Earth and space science is concerned with the study of the planets and stars is

A. Astronomy

Explanation:

A.Astronomy:

'Astron' means stars and 'nomos' means laws. So astronomy is the study of stars , planets and space

B. biology

It is derived from Greek word : 'Bios' means life and 'logos' means study.

Biology is study of life, living organism ,structure of organisms,evolution

C.Geology

It is the earth science which includes the study of rocks and solid earth, what it is made of and how it has changed .

D. Oceanography

It is the study of physical and biological aspects of oceans

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Heat is transferred by conduction through a wall of thickness 0.87 m. What is the rate of heat transfer if the walls thermal con
erik [133]

Explanation:

The given data is as follows.

         Thickness (dx) = 0.87 m,       thermal conductivity (k) = 13 W/m-K

        Surface area (A) = 5 m^{2},       T_{1} = 14^{o}C

        T_{2} = 93^{o}C

According to Fourier's law,

                    Q = -kA \frac{dT}{dx}

Hence, putting the given values into the above formula as follows.

                      Q = -kA \frac{dT}{dx}

                          = -13 W/m-k \times 5 m^{2} \times \frac{(14 - 93)}{0.87 m}

                          = 5902.298 W

Therefore, we can conclude that the rate of heat transfer is 5902.298 W.

4 0
3 years ago
The organelle is found in plant cells contains a green pigment and is the site of photosynthesis. this organelle is the _______
Liono4ka [1.6K]
Answer: Chloroplasts
Reasoning: I just had my 830th lesson in school about these
7 0
2 years ago
A single penny is 1.52 mm thick. The distance to the next nearest star other than our own (Alpha Centauri) is 4.22 light-years.
crimeas [40]

Answer:

2.29 × 10⁴ times

Explanation:

A single penny is 1.52 mm thick. The distance covered by 1 mole of pennies (6.02 × 10²³ pennies) is:

6.02 × 10²³ p × (1.52 mm/1 p) = 9.15 × 10²³ mm = 9.15 × 10²³ × 10⁻³ m = 9.15 × 10²⁰ m

The distance to the next nearest star other than our own (Alpha Centauri) is 4.22 light-years. Considering 1 ly = 9.46 × 10¹⁵ m, this distance in meters is:

4.22 ly × (9.46 × 10¹⁵ m/1 ly) = 3.99 × 10¹⁶ m

The times that the stack would go between the earth and Alpha Centauri are:

9.15 × 10²⁰ m / 3.99 × 10¹⁶ m = 2.29 × 10⁴

8 0
3 years ago
A hypothesis is best written as ?
Nezavi [6.7K]

Answer:

A good experimental hypothesis can be written as an if, then statement to establish cause and effect on the variables. If you make a change to the independent variable, then the dependent variable will respond

8 0
2 years ago
8. A saturated solution of Ag Croq has a silver-ion concentration of 1.3 x 10-4M. Which is the Ksp of Ag CrO 4?
yawa3891 [41]

Answer: The K_{sp} of AgCrO_{4} is 1.1 \times 10^{-12}.

Explanation:

Given: [Ag^{+}] = 1.3 \times 10^{-4} M

The reaction equation will be written as follows.

Ag_{2}CrO_{4} \rightleftharpoons 2Ag^{+} + CrO^{2-}_{4}

This shows that the concentration of CrO^{2-}_{4} is half the concentration of Ag^{+} ion. So,

[CrO^{2-}_{4}] = \frac{1.3 \times 10^{-4}}{2}\\= 0.65 \times 10^{-4} M

The expression for K_{sp} of this reaction is as follows.

K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]

Substitute values into the above expression as follows.

K_{sp} = [Ag^{+}]^{2}[CrO^{2-}_{4}]\\= (1.3 \times 10^{-4})^{2} \times 0.65 \times 10^{-4}\\= 1.1 \times 10^{-12}

Thus, we can conclude that the K_{sp} of AgCrO_{4} is 1.1 \times 10^{-12}.

6 0
3 years ago
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