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3 years ago

Use the drop-down menus to identify each type of sedimentary rock.

Chemistry

2 answers:

prisoha [69]3 years ago

7 0

Answer:

organic, chemical, clastic

Explanation: right on edg 2020

ladessa [460]3 years ago

5 0

rocks form where the remains of plants and animals are deposited in layers.

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How does milk of magnesia act to calm an upset stomach

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It helps an upset stomach by taking out water from the intestines. the milk of magnesia acts as a laxative. or known as (osmotic-type)

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3 years ago

Read 2 more answers

Given 450.98 g of Cu(NO3)2, how many moles of Ag can be made? Provide your final answer rounded to two decimal places.

vivado [14]

Answer:

4.82 moles of Ag.

Explanation:

We'll begin by calculating the number of mole in 450.98 g of Cu(NO₃)₂. This can be obtained as follow:

Molar mass of Cu(NO₃)₂ = 63.5 + 2[14 + (16×3)]

= 63.5 + 2[14 + 48]

= 63.5 + 2[62]

= 63.5 + 124

= 187.5 g/mol

Mass of Cu(NO₃)₂ = 450.98 g

Mole of Cu(NO₃)₂ =?

Mole = mass /Molar mass

Mole of Cu(NO₃)₂ = 450.98 / 187.5

Mole of Cu(NO₃)₂ = 2.41 moles

Next, we shall determine the number of mole of Cu needed to produce 450.98 g (i.e 2.41 moles) of Cu(NO₃)₂. This can be obtained as follow:

Cu + 2AgNO₃ —> Cu(NO₃)₂ + 2Ag

From the balanced equation above,

1 mole of Cu reacted to produce 1 mole of Cu(NO₃)₂.

Therefore, 2.41 moles of Cu will also react to produce 2.41 moles of Cu(NO₃)₂.

Thus, 2.41 moles of Cu is needed for the reaction.

Finally, we shall determine the number of mole of Ag produced from the reaction. This can be obtained as follow:

From the balanced equation above,

1 mole of Cu reacted to produce 2 moles of Ag.

Therefore, 2.41 moles of Cu will react to produce = 2× 2.41 = 4.82 moles of Ag.

Thus, 4.82 moles of Ag were obtained from the reaction.

6 0

3 years ago

4. A piece of metal weighing 0.0713 g was placed in a eudiometer containing dilute aqueous HCl. After the metal fully dissolved,

Anastasy [175]

Complete Question

4. A piece of metal weighing 0.0713 g was placed in a eudiometer containing dilute aqueous HCl. After the metal fully dissolved, 23.5 mL of hydrogen gas was collected by displace-ment of water and a 400 mm column of water was observed. The water temperature was 258C and the barometric pressure was 758.8 mm Hg (torr). Refer to the Introduction and data sheet to solve the following problems.

a) What is the vapor pressure of the water vapor in the column? (Consult Appendix E.)

b) What is the pressure of the water column expressed in mm Hg (torr)? The density of mercury is 13.6 g/mL.

c) Calculate the pressure of the hydrogen gas above the water in the column.

d) Calculate the volume occupied by the hydrogen gas at STP.

Answer:

a) $25\textdegree C=23.8 torrs$

b) $P_w=758.8$

c) $P_w=758.8=735torr$

d) $V_2=20.82mL$

Explanation:

From the question we are told that:

Metal weight $M_m=0.0713g$

Volume Hydrogen $V_h=23.5mL$

Displace-ment Column of water 400 mm column of water

Temperature $T =258\textdegree C$

Barometric Pressure $p=758.8mmHg$

Vapour Pressure of water at $25^oC$

Generally from (Consult Appendix E.)

Va-pour Pressure of water at

$25\textdegree C=23.8 torrs$

Pressure of Water column

$P_w=758.8$

c) Pressure of Water column (Consult Appendix E.)

$P_w=758.8=735torr$

Generally the equation for ideal gas is mathematically given by

$\frac{p_1v_1}{T_1}=\frac{p_2v_2}{T_2}$

Therefore

$V_2=\frac{p_1V_1T_2}{T_1p_2}$

$V_2=\frac{735*23.5*273}{298*760}$

$V_2=20.82mL$

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3 years ago

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The answer to this question is 2 and 3

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4 years ago

What solubility a measure of

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Solubility: the ability for a given substance (the solute) to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium

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4 years ago