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nasty-shy [4]
3 years ago
12

When a meteor falls on earth. a streak of light is seen. will this streak of light be seen if a meteor falls on the moon? Explai

n??
​
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

No streak of light will appear.

Reason I given below.

Explanation:

No streak of light will be seen.

This is because as it falls to the moon, the gravitational pull plus the dense atmosphere which was necessary to produce friction when it fell to the earth are not present in this case and as such the whole meteor is not burnt like it did when it fell to the earth.

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A corpse discovered in the desert at 5:00 PM was found to have larvae from the blow fly species Phormia regina that had just dev
horrorfan [7]

Answer:

12.19 hours prior to discovery was the corpse placed in the desert.

Explanation:

Heat required for fly eggs to develop into first instar larvae = Exposure\,time\times temperature

From the given,

Exposure time = 16 hrs

Temperature = 27 C

=16\times 27 = 427.2^{o}C

The day time exposed hours is 10 hrs.-(7.00am-5.00pm)

=10\times 37.8 = 378^{o}C

So, the extra heat  = 427.2-378= 49.2

The addition heat divided by average temperature.

Average temperature = 22.4 C

=\frac{49.2}{22.4}= 2.19 hrs

So, the total time exposed is night time hours to day time hours.

= 10+2.19 = 12.19 hrs.

Therefore, 12.19 hours prior to discovery was the corpse placed in the desert.

3 0
3 years ago
Convert 32 Fahrenheit to Celsius
valina [46]

Answer:

°F - 32/1.8000

Explanation:

8 0
3 years ago
A chemist measures the energy change ?H during the following reaction:
Leno4ka [110]

Answer:

(A) endothermic

(A) Yes, absorbed

Explanation:

Let's consider the following thermochemical equation.

2 Fe₂O₃(s) ⇒ 4 FeO(s) + O₂(g)  ΔH = 560 kJ

Since ΔH > 0, the reaction is endothermic.

We can establish the following relations:

  • 560 kJ are absorbed when 2 moles of Fe₂O₃ react.
  • The molar mass of Fe₂O₃ is 160 g/mol.

Suppose 66.6 g of Fe₂O₃ react. The heat absorbed is:

66.6g.\frac{1mol}{160g} .\frac{560kJ}{2mol} =117kJ

5 0
4 years ago
If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
1. Patient is admitted with neck injury which has resulted in a loss of function in their thyroid.
Vladimir [108]

Answer:

A. (i think)

Explanation:

3 0
3 years ago
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