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nasty-shy [4]
2 years ago
12

When a meteor falls on earth. a streak of light is seen. will this streak of light be seen if a meteor falls on the moon? Explai

n??
​
Chemistry
1 answer:
Lera25 [3.4K]2 years ago
7 0

Answer:

No streak of light will appear.

Reason I given below.

Explanation:

No streak of light will be seen.

This is because as it falls to the moon, the gravitational pull plus the dense atmosphere which was necessary to produce friction when it fell to the earth are not present in this case and as such the whole meteor is not burnt like it did when it fell to the earth.

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A chemist titrates 150.0 mL of a 0.2653 M carbonic acid (H2CO3) solution with 0.2196 M NaOH solution at 25 °C. Calculate the pH
xxTIMURxx [149]

Answer:

9.3

Explanation:

This is long and complicated so get ready

We are going to use the conjugate base of carbonic acid with water to make carbonic acid and OH- (Na is simply a spectator ion and is irrelavent here)

Let the conjugate base be A- and Carbonic acid be HA

A- + H20 ⇄ HA + OH-

To find the concentration of A- we must find the concentration of the reactants given. We know this will be equal because it is a strong base and all of it disassociates.

to get moles of acid we take the concentration and multiply by liters to cancel

.2653 x .150 = .039795 mol HA

Because it is at equivalence point we know the moles will be equal. We are given the concentration so we only have to solve for liters

We plug it into the equation and found: .181 L

Now use moles and combined volums to fins concentrarion which is .120 M

Now plug that use the Ka converted to Kb to find the cincentrations of HA and OH-

Ka is (10^-3.60) = 2.4E-4

Kb x Ka is 10^-14

Kb = 3.98E-11

Now we know Kb = [HA] [OH] / [A-]

Solve for this through algebra by using x for the values you dont know

youll find x^2 = 3.3E-10

X = 1.8 E -5

this is the OH- concentration

-log [oh] = pOH

pOH = 4.73

We know 14-pOH = ph so pH= 9.3

6 0
3 years ago
What effect does heating a solid to a hightemperature have have on its crystal lattice ??
kotegsom [21]

Arrangement of atoms or group of atoms in a three dimensional ordered pattern in a crystal is said to be a crystalline lattice. They are arranged in a specific pattern with high symmetry. The heating of the crystal at high temperature will result in the increase of vibrational kinetic energy of the atoms in the crystal and this will result in the breaking of lattice apart and due to the breaking of lattice apart the ions will flow freely.

Thus, the heating of a solid at high temperature will lead to the lattice breaks apart and ions will flow freely.

6 0
3 years ago
Read 2 more answers
Which of the following is not an antioxidant _________
Andrews [41]

Answer: 1. Sodium Benzoate

Explanation: An anti-oxidant is a substance that can help prevent or stop the damage done by free radicals. Examples include; Sulphur Dioxide, Sulphite Salts, Citric Acid, e.t.c

Sodium benzoate is a pure preservative.

7 0
2 years ago
Compare and contrast an electric generator and a battery??
anygoal [31]
Both generators and batteries both convert a form of energy into electrical energy. In a battery, a chemical reaction takes place which converts chemical energy into electrical energy. In a generator however, many times mechanical energy is being converted into electrical energy. A process called electromagnetic induction can take place in some generator which is where an electromagnet is used to help conduct electricity. hope this helped!!! 
3 0
3 years ago
How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant
schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

  • 1 g = 1,000 mg
  • The molar mass of Cu is 63.55 g/mol
  • When 1 mole of Cu is deposited, 2 moles of electrons circulate.
  • The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
  • 1 A = 1 C/s

The time  that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s

3 0
3 years ago
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