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QveST [7]
2 years ago
8

23. When solid material is mixed with other solid materials, the materials can be easily

Chemistry
2 answers:
Fantom [35]2 years ago
8 0

Answer:

I think the answer is D:mixed materials.

But I am not sure. I might be nothing or B. Not sure..

dmitriy555 [2]2 years ago
3 0

Answer:

It’s the 3 one

Explanation:

Also I think it’s suppose to be

a

b

c

d

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Is there any organism on the food web that could completely die out that would have no impact on other organisms? Why or why not
andrew11 [14]
Yes because obviously some other organism lives off eating that organism so if they die off the other organisms will be affected heavily
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2 years ago
Question 2
Pavel [41]
Tearing paper, Physical Change
6 0
3 years ago
Free Energy
ratelena [41]

Answer:

a) galvanic cell

b)electrolytic cell

c) i) K=6.27x10'34

ΔG°=198790 J

ii) K=3.58x10'-34

ΔG°= 191070 J

d) E°=0.278 v

ΔG°= -26827 J

Explanation:

a) There are two kinds of an electrochemical cell, the first is called "galvanic cells", and the second "electrolytic cell".

The fuel cells are capable of produce electric energy through chemical reactions. These reactions are often spontaneous. So, the galvanic cell has a negative value for Gibbs free energy.

b) The electrolytic cell increases the value of Gibbs energy, to positive values, due to the reactions are not spontaneous.

c) i) look image attached

ii) k = look image attached

ΔG° = -nFE° = - 6 X 95500 J/vmole x (-0.33 v)

ΔG° =-191070

d) E°= 0.0592 v/n x lg K

E°= 0.0592V / 1 X log 5.0X10'4

E°= 0.278 v

ΔG° = -nFE° = -1 x 96500 J/ vmole x 0.278v

ΔG° = -26827 J

5 0
3 years ago
What is stoichiometry in chemistry?
Ugo [173]

Answer: Stoichiometry is the process of comparing the individual qualitative or numerical variables of the reactants or products involved in a chemical reaction.

Explanation:

4 0
3 years ago
Read 2 more answers
A sample of gas occupies 40.0 mL at -123°C. What volume does the sample occupy at 27°C if the pressure is held constant? V1T2 =
Brums [2.3K]

Answer:

80mL

Explanation:

Step 1:

Data obtained from the question.

Initial Volume (V1) = 40mL

Initial temperature (T1) = –123°C

Final temperature (T2) = 27°C

Final volume (V2) =..?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

T(K) = T(°C) + 273

Initial temperature (T1) = –123°C =

–123°C + 273 = 150K

Final temperature (T2) = 27°C = 27°C + 273 = 300K

Step 3:

Determination of the final volume.

This can be obtained as follow:

V1/T1 = V2/T2

Initial Volume (V1) = 40mL

Initial temperature (T1) = 150K

Final temperature (T2) = 300

Final volume (V2) =..?

V1/T1 = V2 /T2

40/150 = V2 /300

Cross multiply

150 x V2 = 40 x 300

Divide both side by 150

V2 = (40 x 300) /150

V2 = 80mL

Therefore, the new volume of the gas is 80mL

6 0
3 years ago
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