Which of the following is the type of rock
1 answer:
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Answer:
E = 420.9 N/C
Explanation:
According to the given condition:
where,
E = Magnitude of Electric Field = ?
v = speed of charge = 230 m/s
B = Magnitude of Magnetic Field = 0.61 T
θ = Angle between speed and magnetic field = 90°
Therefore,
<u>E = 420.9 N/C</u>
Answer:
(Fuerza de repulsión/Repulsive force)
Explanation:
La fuerza ejercida entre las dos partículas se calcula por la Ley de Coulomb (The force exerted between the two particles is determined by Coulomb's Law):
Donde (Where):
- Constante electrostática, medido en
(Electrostatic constant, measured in
).
,
- Magnitudes de las cargas de cada partícula, medidos en Coulombs. (Magnitudes of charges from each particle, measured in Coulombs).
- Distancia entre las partículas, medida en metros.
La fuerza electrostática es (Electrostatic force is):
Dado que las partículas tienen el mismo signo de carga, la fuerza es de repulsión. (Given that both particles have the same charge sign, the force is of repulsive nature)
Answer: Normal force, N = 141.64 Newton
Explanation:
All the forces acting on the system and described in free body diagram are:
1) gravitational pull in downward direction
2) Normal force in upward direction
3) External force of 40 N acting at an angle of 37° with the horizontal can be resolved in two rectangular components:
i) F Cos 37° along the horizontal plane in forward direction and
ii) F Sin 37° along the vertical plane in downward direction
Applying the Newton's second law, net forces in the vertical plane are:
Net force, f = N - (mg + F Sin 37°)
As there is no acceleration in the vertical plane hence, net force f = 0.
So,
N - (mg + F Sin 37°) = 0
Adding (mg + F Sin 37°) both the sides in above equation, we get
N = mg + F Sin 37°
N = 12 9.8 + 40
0.601 because (Sin 37° = 0.601)
N = 117.6 + 24.04
N = 141.64 Newton
