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2 years ago

If you know what a JW is LET ME KNOW and it is a type of ppl

Physics

2 answers:

Cloud [144]2 years ago

6 0

Answer:

WATAJA ASKIUSMI DEL COCOCHO?!

Explanation:

AH!

lisabon 2012 [21]2 years ago

3 0

Answer:

only thing I think of when I see that is 'Just Wondering'

Explanation:

You might be interested in

The 88-lb force P is applied to the 210-lb crate, which is stationary before the force is applied. Determine the magnitude and d

Marina86 [1]

Answer:

$F=-88Ib$

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

$Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)$

$F=u*N$

with $\mu =0.47$

$F=98.7Ib$

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

$F=-88Ib$

5 0

2 years ago

A uniformly charged, straight filament 5.10 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder

Ratling [72]

Answer:

70509.8039216 N/C

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = 2.00 µC

l = Length of filament = 5.1 m

r = Radius of cylinder = 10 cm

$\lambda=\dfrac{q}{l}$

Electric field is given by

$E=\dfrac{2k\lambda}{r}\\\Rightarrow E=\dfrac{2\times 8.99\times 10^9\times \dfrac{2\times 10^{-6}}{5.1}}{10\times 10^{-2}}\\\Rightarrow E=70509.8039216\ N/C$

The electric field at the surface of the cylinder is 70509.8039216 N/C

7 0

3 years ago

Read 2 more answers

All types of mass movement are caused by the force of

PilotLPTM [1.2K]

Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

6 0

3 years ago

Read 2 more answers

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N, find the coefficient of kinetic

Stolb23 [73]

Answer:

The coefficient of kinetic friction = 0.026

Explanation:

An 56 kg sled is being pulled across the snow, at constant speed,by a horizontal force of 15 N.

Here we have to note that the weight is pulled at a constant speed . This means that the net force acting on the weight is zero.

The external force acting on the body is in the forward direction and the friction acts in the backward direction.

Friction increases as the mass of the body increases.

Friction = $u_{k}\times m \times g$

We now equate this to the external force of 15 N.

15 = $u_{k} \times 56 \times 10$

$u_{k}$ = $\frac{15}{560}$

$u_{k}$ = 0.026

The coefficient of kinetic friction = 0.026

8 0

3 years ago

If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass

sergij07 [2.7K]

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

$m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}$

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

$2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3$

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

$Time = (n)(Half-Life)\\Time =(3)(2\ years)$

<u>Time = 6 years</u>

3 0

2 years ago