Answer:
v = K √(E / ρ)
Explanation:
Modulus of elasticity has units of N/m², or kg/m/s².
Density has units of kg/m³.
Velocity has units of m/s.
If we divide modulus of elasticity by density, we can eliminate kg:
E / ρ = [kg/m/s²] / [kg/m³]
E / ρ = [m²/s²]
Taking the square root gets us units of velocity:
√(E / ρ) = [m/s]
Multiply by the constant K:
v = K √(E / ρ)
Answer:
Time= 6.12*10^4s
mass flow rate m=0.98kg/s
Explanation:
Given
Volume= 60m^3
diamter= 2.5cm= 0.025m
radius= 0.0125m
area A= πr^2
area A= 3.142*0.0125^2
area A= 4.9*10^-4m^2
the velocity of the flow 2m/s
<u>volume flow rate </u>
V=vA
V=2* 4.9*10^-4
V=9.82*10^-4 m^3/s
<u>Time taken to fill the pool</u>
time= volume/volume flow rate
time= 60/9.82*10^-4
time= 6.12*10^4s
<u>Mass flow rate </u>
m= density *volume flow rate
Assuming the density of water to be 997kg/m^3
m= 997*9.82*10^-4
m=0.98kg/s
Your answer is C)
a)t=2.78 sec
b)R=835.03 m
c)
Explanation:
Given that
h= 38 m
u=300 m/s
here given that
The finally y=0
So
t=2.78 sec
The horizontal distance,R
R= u x t
R=300 x 2.78
R=835.03 m
The vertical component of velocity before the strike
The correct answer is false.
Distance between the focal point and the center of the lens