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PIT_PIT [208]
3 years ago
14

What is projectile. what is projectile motion​

Physics
2 answers:
GenaCL600 [577]3 years ago
5 0
<h3> Projectile:</h3>

The projectile is any object thrown into space upon which the only acting force is gravity. In other words, the primary force acting on a projectile is gravity. This doesn’t necessarily mean that the other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory. A baseball batted or thrown and the instant the bullet exits the barrel of a gun are all examples of the projectile.

<h3> Projectile Motion:</h3>

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration that is directed towards the center of the earth (we assume that the particle remains close to the surface of the earth). The path of such a particle is called a projectile and the motion is called projectile motion. Air resistance to the motion of the body is to be assumed absent in projectile motion.

In a Projectile Motion, there are two simultaneous independent rectilinear motions:

Along the x-axis: uniform velocity, responsible for the horizontal (forward) motion of the particle.

Along y-axis: uniform acceleration, responsible for the vertical (downwards) motion of the particle.

Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward. There is no acceleration in the horizontal direction, which means that the velocity of the particle in the horizontal direction remains constant.

zhenek [66]3 years ago
3 0

Explanation:

If an object is given an initial velocity in any direction and then allowed to travel freely under gravity, it is called a projectile motion

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What is the mass, in grams, of 2.00 moles of H2O?
tia_tia [17]

Answer:

36g

Explanation:

Given parameters:

Number of moles of H₂O = 2moles

Unknown:

Mass of  H₂O = ?

Solution:

To solve this problem, use the expression below:

   Mass of  H₂O = number of moles x molar mass

Molar mass of  H₂O = 2(1) + 16  = 18g/mol

  Mass of  H₂O = 2 x 18  = 36g

3 0
3 years ago
if a kid is practicing for a play and there is an auditorium of loud people that are shouting, and he screams, he hears and echo
Vilka [71]
Because the sound waves are being observed by the people that are there and it is not empty as in an empty place the sound waves will come back to you.
5 0
3 years ago
A 75.0 kg ball is rolling at a speed of 57.0 m/s. Calculate the ball’s momentum.
Lubov Fominskaja [6]

4275.

To find momentum you just have to multiply mass and velocity.

4 0
3 years ago
At 2 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast i
labwork [276]

Answer:

The distance between the ships changing at 6PM is 21.29Km/h

Explanation:

Ship A is sailing east at 35Km/h and ship B is sailing West at 25Km/h

Given

dx/dt= 35

dy/dt= 25

dv/dt= ???? at t= 6PM - 2PM= 4

Therefore t=4

We know ship A travels at 150km in the x-direction and Ship A at t=4 travels at 4.35 Which is 140 also in x-direction

So, we use:

D^2 = (150 - x)^2 + y^2;

D^2 = (150 - 140)^2 + y^2

But ship B travels at t=4, at 4.25 =100 in the y-direction

so, let's use the equation:

D^2 = 10^2 + 100^2

= D= sqrt*(10 + 100)

Lets use 2DD' = 2xx' + 2yy'

Differentiating with respect to t we have:

D•d(D)/dt = -(10)•dx/dt + 100•dy/dt

=100.5 d(D)/dt = (-10)•35 + (100)•25

When t=4, we have x=(140-150) =10 and y=100

= D = sqrt*(10^2 + 100^2)

=100.5

= 100.5 dD/dt = 10.35 +100.25

= dD/dt = 21.29km/h

7 0
3 years ago
After the elevator accelerates, then it moves at a constant speed of 6.0m/s, calculate the tension inthe cable.
Anon25 [30]

We know that

• The mass of the elevator is 5000 kg.

Let's draw a free-body diagram.

As you can observe, there are just two forces involved, the weight of the elevator and the tension force. Let's use Newton's Second Law.

\begin{gathered} \Sigma F_y=ma_y \\ T-W=ma_y \end{gathered}

But, W = mg = 5000kg*9.8m/s^2 = 49,000 N, and m = 5000 kg, a = 0 (because the speed is constant).

\begin{gathered} T-49,000N=5000\operatorname{kg}\cdot0 \\ T=49,000N \end{gathered}<h2>Therefore, the tension in the cable is 49,000 N.</h2>

3 0
1 year ago
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