Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor
1 answer:
Answer:
A dissipates more power.
Explanation:
- In a series circuit, the current is the same at any point in it.
- The power dissipated in any resistor follows Joule's law, as follows:
- So, for a given current, the power is directly proportional to the resistance of the resistor.
- In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.
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Answer:
The maximum no. of electrons-
Solution:
As per the question:
Maximum rate of transfer of charge, I = 1.0 C/s
Time, t = 1.0 h = 3600 s
Rate of transfer of charge is current, I
Also,
Q = ne
where
n = no. of electrons
Q = charge in coulomb
I = current
Thus
Q = It
Thus the charge flow in 1. 0 h:
Maximum number of electrons, n is given by:
where
e = charge on an electron =
Thus