Question

Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor dissipates more power

Answer 1

Answer:

A dissipates more power.

Explanation:

• In a series circuit, the current is the same at any point in it.
• The power dissipated in any resistor follows Joule's law, as follows:

        $P = I^{2} * R$

• So, for a given current, the power is directly proportional to the resistance of the resistor.
• In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.