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Sav [38]
3 years ago
9

Two resistors, A and B, are connected in a series circuit with a battery. The resistance of A is twice that of B. Which resistor

dissipates more power
Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

A dissipates more power.

Explanation:

  • In a series circuit, the current is the same at any point in it.
  • The power dissipated in any resistor follows Joule's law, as follows:

        P = I^{2} * R

  • So, for a given current, the power is directly proportional to the resistance of the resistor.
  • In this case, as resistor A has twice the resistance of resistor B, A dissipates twice more power than B.
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25 points and i will give brainliest +5 star rating to a correct a correct answer!!!!
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Answer:

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Explanation:

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n = 1.52

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v = 1.9736 * 10^8

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Give 2 reasons for fitting heavy commercial vehicles with many tyres​
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Air, considered an ideal gas, is contained in an insulated piston-cylinder assembly outfitted with a paddle wheel. It is initial
Maru [420]

Our data are,

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P_1= 10psi=68.95kPa\\V_1 = 1ft^3=0.02831m^3\\T_1 = 100\°F = 310.93K

State 2:

P_2 =5psi=34.474kPa\\V_2 = 3ft^3=0.0899m^3

We know as well that 3BTU=3.16kJ/K

To find the mass we apply the ideal gas formula, which is given by

P_1V_1=mRT_1

Re-arrange for m,

m= \frac{P_1V_1}{RT_1}\\m= \frac{68.95*0.02831}{(0.287)310.9}\\m=0.021893kg=0.04806lbm\\

Because of the pressure, temperature and volume ratio of state 1 and 2, we have to

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

Replacing,

T_2 = \frac{P_2V_2}{P_1V_1}T_1\\T_2 =\frac{34.474*0.0844}{68.95*0.02831}*310.93\\T_2 = 464.217K=375.5\°F

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3 0
3 years ago
A closely wound circular coil has a radius of 6.00 cmand carries a current of 2.65 A. How many turns must it have if the magneti
ad-work [718]

Answer:

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radius of the coil, R = 6 cm = 0.06 m

current in the coil, I = 2.65 A

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B = \frac{\mu_{o}NI}{2R}

Therefore,

N = \frac{2BR}{\mu_{o}I}

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8 0
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avanturin [10]

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Explanation:

4 0
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