Answer:
155.38424 K
2.2721 kg/m³
Explanation:
= Pressure at reservoir = 10 atm
= Temperature at reservoir = 300 K
= Pressure at exit = 1 atm
= Temperature at exit
= Mass-specific gas constant = 287 J/kgK
= Specific heat ratio = 1.4 for air
For isentropic flow
The temperature of the flow at the exit is 155.38424 K
From the ideal equation density is given by
The density of the flow at the exit is 2.2721 kg/m³
Answer:
Its final velocity and how much time it takes to reach the water
Explanation:
The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration of gravity
s = 52 m is the distance covered during the fall
Solving for v,
We can also find how much time it takes to reach the water, using the equation
where
v = 31.9 m/s is the final velocity
u = 0 is the initial velocity
t is the time
And solving for t,