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amm1812
3 years ago
5

Container A has 1600 ml of water and is leaking 12 ml per minute. Container B has 2000 ml and is leaking 20 ml per minute. Let m

represest the number of minutes the contains are leaking. How many minutes, m, will it take for the two containers to have the same amount of water? Write and solve an equation to show your work.
Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

Container A i remember this question from years back

Step-by-step explanation:

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Lines a and b are parallel. The slope of line b is * What is the slope of line a?
andrew11 [14]

Answer:

The slope of line a is * also.

Step-by-step explanation:

Parallel lines have the same slope. Whatever number, fraction, variable, symbol is given for the slope of one line, the other must have the same number, fraction, variable, symbol, if they are parallel.

5 0
2 years ago
A wedding planner uses 72 ivy stems for 18 centerpieces when she arrives at the venue she realizes she will only need 16 centerp
beks73 [17]

Answer:

64 ivy stems

Step-by-step explanation:

To solve this problem we can use rule of three:

Firstly we had 72 ivy stems to use in 18 centerpieces, and know we have 16 centerpieces and want to know how many ivy stems we need to use, so:

18 centerpieces -> 72 ivy stems

16 centerpieces -> X ivy stems

18/16 = 72/X

X = 16*72/18 = 64

He needs to use now 64 ivy stems to maintain the ratio.

6 0
3 years ago
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Two buses are moving towards each other, one at a speed of 40 mph and the other at a speed of 50 mph. How much closer to each ot
steposvetlana [31]
What is the starting distance
3 0
3 years ago
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usa el teorema de la altura para proponer como se podria construir un segmento cuya longitud sea media proporcional entre dos se
Mrac [35]
Usando el teorema de altura 

El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que e<span>n todo </span>triángulo rectángulo, la altura (h<span>) relativa a la </span>hipotenusa<span> es la </span>media geométrica<span> de las dos proyecciones de los </span>catetos<span> sobre la </span>hipotenusa<span> (</span>n<span> y </span>m<span>). Es decir, se cumple que:

</span>\frac{n}{h}= \frac{h}{m}

Dado que el problema establece <span>construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:

</span>\frac{4}{h}= \frac{h}{9}

De donde:

h= \sqrt{(4)(9)}=\sqrt{36}=6cm

¿Cómo se podria construir si los segmentos son de a cm y b cm?

Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:

h= \sqrt{ab}

6 0
3 years ago
If I had a large square with 12 small squares shaded what percentage of the square is shaded
zhuklara [117]

<span>12% = 12 percent = 12 parts out of 100 = 12/100</span>

<span>i hope thin helped 
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6 0
3 years ago
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