Answer:
In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory.
Explanation:
a) At a position of 2.0m, the Initial energy is
all made up of the potential energy=m*g*hi<span>
and meanwhile at 1.5 all its energy is also potential energy=m*g*hf
The percentage of energy remaining is E=m*g*hi/m*g*hf x 100
and since mass and gravity are constant so it leaves us with
just E=hi/hf
which 1.5/2.0 x100= 75% so we see that we lost 25% of the
energy or 0.25 in fraction
b) Here use the equation vf^2=vi^2+2gd
<span>where g is gravity, vf is the final velocity and vi is the
initial velocity while d is the distance travelled
so in here we are looking for the vi so let us isolate that
variable
we know that at maximum height or peak, the velocity is 0 so
vf is 0
therefore,</span></span>
vi =sqrt(-2gd) <span>
vi =sqrt(-2x-9.81x1.5) </span>
<span>vi =5.4 m/s
<span>c) The energy was converted to heat due to friction with the
air and the ground.</span></span>
Answer:
compacting
Explanation:
i don't think there is very much explanation, the snow falls and compacts the ice to become giant lol
Answer:
15.07 ksi
Explanation:
Given that:
Pitch (P) = 5 teeth/in
Pressure angle (
) = 20°
Pinion speed (
) = 2000 rev/min
Power (H) = 30 hp
Teeth on gear (
) = 50
Teeth on pinion (
) = 20
Face width (F) = 1 in
Let us first determine the diameter (d) of the pinion.
Diameter (d) =
=![\frac{20}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B5%7D)
= 4 in
From the values of Lewis Form Factor Y for (
) = 20 ; at 20°
Y = 0.321
To find the velocity (V); we use the formula:
![V = \frac{\pi d n_p}{12}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Cpi%20d%20n_p%7D%7B12%7D)
![V = \frac{\pi *4*2000}{12}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Cpi%20%2A4%2A2000%7D%7B12%7D)
V = 2094.40 ft/min
For cut or milled profile; the velocity factor
can be determined as follows:
![K_v = \frac{2000+V}{2000}](https://tex.z-dn.net/?f=K_v%20%3D%20%5Cfrac%7B2000%2BV%7D%7B2000%7D)
![K_v = \frac{2000+2094.40}{2000}](https://tex.z-dn.net/?f=K_v%20%3D%20%5Cfrac%7B2000%2B2094.40%7D%7B2000%7D)
= 2.0472
However, there is need to get the value of the tangential load
, in order to achieve that, we have the following expression
![W^t=\frac{T}{\frac{d}{2} }](https://tex.z-dn.net/?f=W%5Et%3D%5Cfrac%7BT%7D%7B%5Cfrac%7Bd%7D%7B2%7D%20%7D)
![W^t = \frac{63025*H}{\frac{n_pd}{2}}](https://tex.z-dn.net/?f=W%5Et%20%3D%20%5Cfrac%7B63025%2AH%7D%7B%5Cfrac%7Bn_pd%7D%7B2%7D%7D)
![W^t = \frac{63025*30}{2000*\frac{4}{2}}](https://tex.z-dn.net/?f=W%5Et%20%3D%20%5Cfrac%7B63025%2A30%7D%7B2000%2A%5Cfrac%7B4%7D%7B2%7D%7D)
![W^t = 472.69 lbf](https://tex.z-dn.net/?f=W%5Et%20%3D%20472.69%20lbf)
Finally, the bending stress is calculated via the formula:
![\sigma = \frac{K_vW^tp}{FY}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7BK_vW%5Etp%7D%7BFY%7D)
![\sigma = \frac{2.0472*472.69*5}{1*0.321}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B2.0472%2A472.69%2A5%7D%7B1%2A0.321%7D)
![\sigma = 15073.07 psi](https://tex.z-dn.net/?f=%5Csigma%20%3D%2015073.07%20psi)
15.07 ksi
∴ The estimate of the bending stress = 15.07 ksi
Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question