We are given with
distance traveled through vacuum = 1.0 m
refractive index of water = 1.33
refractive index of glass = 1.50
refractive index of diamond = 2.42
distance traveled through water is = 1.0/1.33 = 0.75 m
distance traveled through water is = 1.0/1.50 = 0.67 m
distance traveled through water is = 1.0/2.42 = 0.41 m
Assuming an ideal gas, the speed of sound depends on temperature
only. Air is almost an ideal gas.
Assuming the temperature of 25°C in a "standard atmosphere", the
density of air is 1.1644 kg/m3, and the speed of sound is 346.13 m/s.
The velocity can't be specified, since the question gives no information
regarding the direction of the sound.
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30
E = 350 * 30
E = 1050 Joules.
So, your answer is 1050 Joules.
Hope this helps! Keep studying!
since both components, length and time, are measurable
<span>since Rate = length ÷ time </span>
<span>∴ rate is also measurable and ∴ quantitative.
</span>
.Answer:
The value of the work done is
.
Explanation:
When a charged particle having charge
is moving through an electric field
, the net force (
) on the charge is

and the work done (
) by the particle is

Given,
.
Substitute the value of electric field in equation (1) and then substitute the result in equation (2).
![W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}](https://tex.z-dn.net/?f=W%20%26%3D%26%20%5Cint%5Climits%5E7_0%20%7Bq%5Cdfrac%7BA_%7B0%7D%7D%7Bx%5E%7B1%2F2%7D%7D%7D%20%5C%2C%20dx%20%5C%5C%26%3D%26%20qA_%7B0%7D%20%5Cint%5Climits%5E7_0%20%7Bx%5E%7B-1%2F2%7D%7D%20%5C%2C%20dx%20%5C%5C%26%3D%26%202qA_%7B0%7D%5Bx%5E%7B1%2F2%7D%5D_%7B0%7D%5E%7B7%7D%5C%5C%26%3D%26%205.29%20qA_%7B0%7D)