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andrew11 [14]
3 years ago
7

Which of the following is true about this lever?

Physics
2 answers:
zysi [14]3 years ago
6 0

As we can see here the lever has two forces at two ends

1. 300 N

2. 200 N

now we need to find the Torque on the lever about the fulcrum

so we will have

1. clockwise torque due to force at right end is

\tau_1 = d_1F_1

\tau_1 = 6(200) = 1200 Nm

2. counterclockwise torque due to force at left end

\tau_2 = d_2F_2

\tau_2 = 1(300) = 300 Nm

so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction

so <u>it will rotate clockwise</u>

Artyom0805 [142]3 years ago
4 0

The lever will rotate clockwise.

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Which of the following is the most accurate statement concerning the properties of matter?
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b. they can be observed and measured

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8 0
4 years ago
A compact car has a mass of 1310 kg . Assume that the car has one spring on each wheel, that the springs are identical, and that
Nady [450]

Answer:

a) k= 3232.30 N / m,  b)  f = 4,410 Hz

Explanation:

In this exercise, the car + spring system is oscillating in the form of a simple harmonic motion, as the four springs are in parallel, the force is the sum of the 4 Hocke forces.

The expression for the angular velocity is

          w = √k/m

the angular velocity is related to the period

          w = 2π / T

we substitute

          T = 2\pi  √m/ k

a) empty car

           k = 4π² m / T²

           k = 4 π² 1310/2 2

           k = 12929.18 N / m

This is the equivalent constant of the short springs

           F1 + F2 + F3 + F4 = k_eq x

           k x + kx + kx + kx = k_eq x

           k_eq = 4 k

           k = k_eq / 4

           k = 12 929.18 / 4

            k= 3232.30 N / m

b) the frequency of oscillation when carrying four passengers.

In this case the plus is the mass of the vehicle plus the masses of the passengers

            m_total = 1360 + 4 70

            m_total = 1640 kg

angular velocity and frequency are related

              w = 2pi f

we substitute

             2 pi f = Ra K / m

in this case the spring constant changes us

             k_eq = 12929.18 N / m

           

             f = 1 / 2π √ 12929.18 / 1640

             f = π / 2 2.80778

             f = 4,410 Hz

3 0
3 years ago
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