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mina [271]
3 years ago
11

Given an object's mass and observing its acceleration, what can be found in a direct application of Newton's second law of motio

n?
A.
the object's size
B.
the object's initial velocity
C.
the net force on the object
D.
the object's material composition
Physics
1 answer:
Natalka [10]3 years ago
6 0

Answer:

C. the net force on the object

Explanation:

That is because Force= mass x acceleration. The question says that we know the mass and acceleration, which means that it would be the force that resulted in the acceleration of the mass.

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Star-forming clouds appear dark in visible-light photos because the light of stars behind them is absorbed by __________.
Ostrovityanka [42]

Answer:

Interstellar Dust

Explanation:

In the solar system Interstellar dust is a type of cosmic dust and unlike Interstellar gas they have large dust particles enabling them to block visible light. Unlike smoke and fog, they contain large number of closely packed clumps of atoms and molecules

7 0
3 years ago
Read 2 more answers
If the frequency of the 13C signal of TMS is 201.16 MHz, the two 13C signals of acetic acid at 179.0 and 20.0 ppm are separated
Lelu [443]

The difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

The given parameters;

  • <em>frequency of the 13 C signal = 201.16 MHz</em>

The energy of the 13 C signal located at 20 ppm is calculated as follows;

E = hf\\\\E_1 = h \frac{c}{\lambda} \\\\E_1 =  \frac{(6.626 \times 10^{-34})\times 3\times 10^8}{20 \times 10^{-6}} \\\\E_1 = 9.94 \times 10^{-21} \ J

The energy of the 13 C signal located at 179 ppm is calculated as follows;

E_2 = \frac{hc}{\lambda} \\\\E_2 = \frac{(6.626\times 10^{-34})\times (3\times 10^{8})}{179 \times 10^{-6} } \\\\E_2 = 1.11 \times 10^{-21} \ J

The difference in frequency of the two signals is calculated as follows;

E_1- E_2 = hf_1 - hf_2\\\\E_1 - E_2 = h(f_1 - f_2)\\\\f_1 - f_2 = \frac{E_1 - E_2 }{h} \\\\f_1 - f_2 = \frac{(9.94\times 10^{-21}) - (1.11 \times 10^{-21})}{6.626\times 10^{-34}} \\\\f_1 - f_2 = 1.33 \times 10^{13} \ Hz\\\\f_1 - f_2 = 1.33\times 10^{10} \ kHz

Thus, the difference in frequency of the two signals is 1.33 \times 10^{10} \ kHz.

Learn more here:brainly.com/question/14016376

4 0
3 years ago
A given mass of air has a volume of 6.00 L at 101 kPa. At constant temperature, the pressure is decreased to 25.0 kPa. Calculate
Sidana [21]

Answer:

24.24L

Explanation:

According to Boyle's law which states that "the volume of a given mass of gas at constant temperature is inversely proportional to its pressure". Mathematically, P = k/V where;

P is the pressure

V is the volume

k is the proportionality constant

PV = k

P1V1 = P2V2

P1 and P2 are initial and final pressure respectively

V1 and V2 are the initial and final volume respectively

Given P1 = 101kPa V1 = 6.0L, P2 = 25kPa V2 = ?

From the formula;

V2 = P1V1/P2

V2 = 101×6/25

V2 = 24.24L

The final volume for the gas is 24.24L

6 0
3 years ago
Which of the following describes the time over which a periodic wave repeats?
sineoko [7]

Answer:

b

Explanation:

4 0
4 years ago
A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.
Hunter-Best [27]
<span>a solution is a liquid mixture  </span>
4 0
4 years ago
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