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3 years ago

What imaginary line marks the southern end of the tropical zone

2 answers:

5 0

The Tropic of Capricorn is significant to understanding the Earth's geography because it marks the southern boundary of tropics.

Snowcat [4.5K]3 years ago

5 0

Answer:

The tropic of Capricorn

Explanation:

This line runs 23.5 degrees south of the equator.

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The most soaring vocal melody is in Johann Sebastian Bach's Mass in B minor. In one section, the basses, tenors, altos, and sopr

solmaris [256]

Answer:

2.33651226158 m

Explanation:

From the question the required data is as follows

f = Frequency of the initial note = 146.8 Hz

v = Velocity of sound in air = 343 m/s

The wavelength of a wave is given by

$\lambda=\dfrac{v}{f}$

$\Rightarrow \lambda=\dfrac{343}{146.8}$

$\Rightarrow \lambda=2.33651226158\ m$

The wavelength of the initial note is 2.33651226158 m

3 0

3 years ago

A solid spherical conductor has a radius of 12 cm. The electric field at 24 from the center of the sphere has a magnitude of 640

hoa [83]

Answer:

Charge density on the sphere = 2.2 × 10⁻⁸ C/m²

Explanation:

Given:

Radius of sphere (r) = 12 cm = 0.12 m

Distance from the electric field R = 24 cm = 0.24 m

Magnitude (E) = 640 N/C

Find:

Charge density on the sphere

Computation:

Charge on the sphere (q) = (1/K)ER² (K = 9 × 10⁹)

Charge on the sphere (q) = [1/(9 × 10⁹)](640)(0.24)²

Charge on the sphere (q) = 4 × 10⁻⁹ C

Charge density on the sphere = q / [4πr²]

Charge density on the sphere = [4 × 10⁻⁹] / [4(3.14)(0.12)²]

Charge density on the sphere = [4 × 10⁻⁹] / [0.18]

Charge density on the sphere = 2.2 × 10⁻⁸ C/m²

4 0

2 years ago

Enunciado del ejercicio n° 1

hoa [83]

Answer:

Explanation:

6 0

2 years ago

A 4.4 kg mess kit sliding on a frictionless surface explodes into two 2.2 kg parts, one moving at 2.9 m/s, due north, and the ot

sp2606 [1]

Answer:

Original speed of the mess kit = 4.43 m/s at 50.67° north of east.

Explanation:

Let north represent positive y axis and east represent positive x axis.

Here momentum is conserved.

Let the initial velocity be v.

Initial momentum = 4.4 x v = 4.4v

Velocity of 2.2 kg moving at 2.9 m/s, due north = 2.9 j m/s

Velocity of 2.2 kg moving at 6.8 m/s, 35° north of east = 6.9 ( cos 35i + sin35 j ) = 5.62 i + 3.96 j m/s

Final momentum = 2.2 x 2.9 j + 2.2 x (5.62 i + 3.96 j) = 12.364 i + 15.092 j kgm/s

We have

Initial momentum = Final momentum

4.4v = 12.364 i + 15.092 j

v =2.81 i + 3.43 j

Magnitude

$v=\sqrt{2.81^2+3.43^2}=4.43m/s$

Direction

$\theta =tan^{-1}\left ( \frac{3.43}{2.81}\right )=50.67^0$

50.67° north of east.

Original speed of the mess kit = 4.43 m/s at 50.67° north of east.

6 0

3 years ago

Please help me whit this question

mariarad [96]

Answer:

Gypsum

Explanation:

Gypsum is a soft sulfate mineral composed of Calcium Sulfate di-hydrate. It is widely used in composition of fertilizer. It is also known as land plaster. On adding gypsum to soil, the quality of soil is improved. It conditions the soil and adds nutrients. The properties of soil is improved. Hence, the correct answer is Gypsum.

Hope this helped:)

pls mark brainlist

6 0

3 years ago