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tiny-mole [99]
3 years ago
14

What imaginary line marks the southern end of the tropical zone

Physics
2 answers:
vitfil [10]3 years ago
5 0
The Tropic of Capricorn is significant to understanding the Earth's geography because it marks the southern boundary of tropics.
Snowcat [4.5K]3 years ago
5 0

Answer:

The tropic of Capricorn

Explanation:

This line runs 23.5 degrees south of the equator.

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What do deltas and natural levees have in common?
Tpy6a [65]
They are both formed by deposited river sediment.
7 0
3 years ago
What exactly is Density? Please answer​
solmaris [256]

Answer:

density is the quantity per a unit volume, unit area or unit length.

Explanation:

7 0
3 years ago
Light travels at a speed of about 3.0 108 m/s. (a) how many miles does a pulse of light travel in a time interval of 0.1 s, whic
babunello [35]

Speed of light is given as

c = 3 * 10^8 m/s

time interval is given as

\Delta t = 0.1 s

so the distance covered by the light is given as

d = v * \Delta t

d = 3 * 10^8 * 0.1 = 3 * 10^7 meter

now as we know that

1 mile = 1609 meter

so the distance moved by light is

d = \frac{3 * 10^7}{1609} = 18645.12 miles

now for the comparision of this distance with diameter of earth

as we know that radius of earth is

R = 6.38 * 10^6 m

so the diameter of earth will be

d = 2R = 12.76 * 10^6 m

now the ratio of diameter with the distance that light move will be

\frac{distance}{diameter} = \frac{3 * 10^7}{12.76 * 10^6}

\frac{distance}{diameter} = 2.35

<em>so it is 2.35 times more than the diameter of earth</em>

4 0
3 years ago
In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x
Ostrovityanka [42]

Answer:

(a) increase

Explanation:

On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.

The change in the potential energy of a charge field-system can be given as:

\delta U= -q(EdsCos \theta)

where;

q = positive test charge

E = Electric field

ds = displacement between thee charge positions

θ  = Angle between the electric field and the displacement.

Given that:

Charge of the particle = -q

displacement = (60.0 -20.0)cm = 40.0 cm

θ = 0

Replacing our values in the above equation, we have:

\delta U = -(-q)(60Cos 0)

\delta U = qEds

Since the potential energy of the system is positive, therefor the electric potential energy also increases.

5 0
4 years ago
How can an experiment support or fail to support a hypothesis?
Alisiya [41]

a hypothesis is given to explain a phenomena which has not been explained earlier. it can proved  by an experiment if that experiment gets the other results regarding that particular phenomena in agreement with that being predicted by the hypothesis and if  result doesnt match the prediction then the hypothesis is again  totally discarded at times.
6 0
3 years ago
Read 2 more answers
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